The system of first order differential equations y₁ = -4y₁ + 5y2 + 1 32 = 5y1 - 4y2 +1 where yı(0) = 0, y2 (0) = 0 has solution y₁ (t)= 4e³t y2(t) = -7e³t
The system of first order differential equations y₁ = -4y₁ + 5y2 + 1 32 = 5y1 - 4y2 +1 where yı(0) = 0, y2 (0) = 0 has solution y₁ (t)= 4e³t y2(t) = -7e³t
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Entered
4*[e^(3*t)]
-7*[e^(3*t)]
At least one of the answers above is NOT correct.
has solution
yı(t)=4e³t
y₂(t) = -7e³t
The system of first order differential equations
y'₁ = −4y1 + 5y2 + 1
y2 = 5y1 - 4y2 +1
where y₁ (0) = 0, y₂ (0) = 0
Answer Preview
4e³t
-7e³t
Result
incorrect
incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F008f31aa-ffde-472d-81b9-49fb75f4a0c2%2F67136e46-8ce6-415a-b5c7-4b98aebf2b9f%2Fryxow0i_processed.png&w=3840&q=75)
Transcribed Image Text:Entered
4*[e^(3*t)]
-7*[e^(3*t)]
At least one of the answers above is NOT correct.
has solution
yı(t)=4e³t
y₂(t) = -7e³t
The system of first order differential equations
y'₁ = −4y1 + 5y2 + 1
y2 = 5y1 - 4y2 +1
where y₁ (0) = 0, y₂ (0) = 0
Answer Preview
4e³t
-7e³t
Result
incorrect
incorrect
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