The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are Sx = 17 MPa, Sy = 29 MPa, and Sxy = 26 MPa. Assume β=tan^−1(b/a)=23.2∘, a = 7, and b = 3. Using the equilibrium equation approach, determine the normal and shear stresses σ (positive if tensile, negative if compressive) and ττ (magnitude only) at this point on the inclined plane shown.

Q: ) Write the equation for the neutral axis in the cross-section. b) Draw the normal stress…

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Q: The stresses shown act at a point in indicated in the figure. Using the ed plane shown. Assume ß =…

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Q: The stresses shown act at a point in a stressed body. The stress magnitudes are Sx = 95 MPa and Sy =…

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Q: indicated in the figure. Using the equilibrium equation approach, determine the normal and shear…

A: Given data in question  Stresses Angle To find out  Normal and shear stresses

Q: The stresses shown act at a point in a stressed body. The stress magnitudes are Sy = 60 MPa and Sy =…

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Q: The stresses shown act at a point in a stressed body. The stress magnitudes are S, = 75 MPa and 5, =…

A: Given data in question  Stresses Angle To find out Normal and shear stress

Q: Q.2) A state of stress is specified as shown in Figure (2), By using Mo determine the normal and…

A: Radius of the circleR=(σx-σy2)2+τxy2R=(40+802)2+502R=78.1…

Q: The stresses shown act at a point in a stressed body.  The stress magnitudes are Sx = 75 MPa and Sy…

A: Given data in question  Normal stresses Angle To find out  Normal and shear stresses

Q: vertical planes at the point are shown. Assume stress magnitudes of Sy-320 MPa, Sxy - 230 MPa.…

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Q: The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on…

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Q: The stresses shown act at a point on the free surface of a machine component. Normal and shear…

A: The given data is shown below: Sx=12.4 ksiSy=3.5 ksiSxy=3.6 ksiβ=29°

Q: The stresses shown act at a point on the free surface of a machine component. Normal and shear…

A: Using transformation equation

Q: POISSON'S RATIO, µ It is the ratio of indirect strain to direct strain Formulas: H= Eindirect…

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Q: equation approach, determine the normal and shear stresses o (positive if tensile, negative if…

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Q: a) Determine the magnitudes, and senses of the direct and shear stresses which

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Q: 2 KN.m 350 mm 50 mm 200 mm columna 175 mm 2 m 1 m 8 m

A: as support are simply suppourted.max BM= BMmax=wl28 =2*828 =16KNM

Q: The stresses shown act at a point in a stressed body. The stress magnitudes are S, = 60 MPa and Sy =…

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Q: ee surface of a machine component. Normal and shear stress magnitudes acting on horizontal and…

A: Radius of the circleR=(sx-sy2)2+sxy2R=(23.6-2.82)2+72R=12.54 ksisAVG=sx+sy2=23.6+2.82sAVG=13.2ksi

Q: We need the following relationships in deriving the transverse shear stress formula, except? Select…

A: Ans = c In derivation of transverse shear stress formula all options are used except c.

Q: In a 2 dimensional stress anal ysis, the state of stress at a point is shown below in which length…

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Q: The stresses shown in the figure act at a point in a stressed body. The stress magnitudes are Sx =…

A: Given: The stress in the x-direction (Sx) is 170 MPa. The stress in the y-direction (Sy) is 85 MPa.…

Q: Plane Stress In the stress element given in Figure 3, WITH MOHR CIRCLE; (a) Determine the principal…

A: Principal stresses: Principal stresses are the utmost and minimum value of normal stresses on a…

Q: In each case, calculate the value of Q and t that are used in the shear formula for finding the…

A: we are authorized to answer up to three subparts for a single post. As you have not mentioned so we…

Q: A cube with a side of a=15 cm is seated in a rigid recess from its five faces, as shown in the…

A: Given data - Length of cube(L) = 15 cm =150 mm Area of cube (A) = (3.14 ×(150^2))/4…

Q: Problem 7.2-18 The surface of an airplane wing is subjected to plane stress with normal stresses o,…

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Q: The stresses shown act at a point in a stressed body. The stress magnitudes are Sx - 60 MPa and Sy=…

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Q: The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on…

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Q: The bending moment Mx affects the cross section of the beam given in Figure 4. Beam cross section…

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Q: The stresses shown act at a point in a stressed body. The stress magnitudes ares, indicated in the…

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Q: The stresses shown act at a point in a stressed body. The stress magnitudes are Sx = 60 MPa and…

A: Given  Sx=60Mpa Sy=-215Mpa

Q: The stresses shown act at a point in a stressed body. The stress magnitudes are S, = 75 MPa and S, =…

A: Given data in question  Normal stress on element  Angle  To find out  Normal and shear stresses

Q: The stresses shown act at a point in a stressed body. The stress magnitudes are Sx = 50 MPa and S, =…

A: Determine the normal and shear stresses at this point on the inclined plane shown.

Q: The normal and shear stresses at a point in a structural subjected to a state of plane stress are…

A: To find principal stress and shear stress and their direction

Q: In a 2 dimensional stress analysis, the state of stress at a point is shown below in which length of…

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Q: Find the normal stress and shear stress in the shaded plane using the MOHR circle for the element in

A: Given that:

Q: The stresses shown act at a point in a stressed body. The stress magnitudes are Sx = 60 MPa and Sy =…

A: Given Data:   Sx=60 Mpa Sy=-230 Mpa β=49°   It is asked to calculate Normal stress and shear…

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.