o4 me thane follows this quemicalThe steam retorming reactionequation=CHycg) t HzOg→ cog) + 3 Hz ca) Apti= + 194 kjlnol- + 194->lies far to the reactant side with7.20 x 10 23. TOthe desired hydrogen9f uery highConst ant atA+298 Kthe reactione quililori umSignificant a movnt ofa verySmallconsdantofob taingas product, the reae tion is operatedtemperatuas.wLat is 44e e quilibriumT100 K?ans wer as a hum loer with no decimal places

The steam reforming reaction me thane follows this quemical equation= CHycg) + HzO g)→ Co g) + 3Hz cg) Aptl = +194 k]lmol <> lies far to the reactant side with Of 7.20 x 1o23. TO s:gnificant a movat of the desired hydrogen 9t very high Const ant qt A+ 298 K the reaction very Small equililon um constant ob tain gas product temperatuas , , the reac tion is operated wLat is 4he equilibrium T100 x? ans wer as a hum loer with no decimal places

The steam reforming reaction me thane follows this quemical equation= CHycg) + HzO g)→ Co g) + 3Hz cg) Aptl = +194 k]lmol <> lies far to the reactant side with Of 7.20 x 1o23. TO s:gnificant a movat of the desired hydrogen 9t very high Const ant qt A+ 298 K the reaction very Small equililon um constant ob tain gas product temperatuas , , the reac tion is operated wLat is 4he equilibrium T100 x? ans wer as a hum loer with no decimal places

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Just do questions no.18 in 20 minutes
46. The following equilibrium pressures were determined for the reaction CO (g) + H₂O (g) PCO = PH20 = 0.44 atm CO₂ (g) + H₂ (g) Pco2 PH2 = 0.556 atm = Calculate dGº for the reaction.
Be sure to answer all parts. Using the data in the table, calculate Kp and AGfor this reaction at 25°C. PC15(g) = PC13(g) + Cl2(g) Initial Partial AG Substance Pressure (kJ/mol) (atm) C2(8) 0.353 PCl3(g) -286 0.216 PCI5(g) -325 0.00290 Кр- X 10 AG = kJ/mol
G71 degrees f to c- Google Search X C help 1,2,4 | Chegg.com gNslkr7j8P3jH-liGOe3ZhgGhYRBIX9D1jAYn5Rlqv6WMd_eBm2W55RqYfXBxKoFtRWtFipNdLz9_G8r90xedbFd57m4ED5 O KINETICS AND EQUILIBRIUM Deducing a rate law from the change in concentration over time time (seconds) A chemistry graduate student is studying the rate of this reaction: H,CO, (aq) — H,O (aq)+CO,(aq) He fills a reaction vessel with H₂CO3 and measures its concentration as the reaction proceeds: 0 0.10 0.20 0.30 0.40 [H₂CO3] 0.0100 M 0.00499 M Explanation 0.00333 M 0.00250 M 0.00200 M Use this data to answer the following questions. Write the rate law for this reaction. Calculate the value of the rate constant k. Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol. Check rate = k X k= 0.0 ALEKS-Mark Heien - Lear X 2 0° S C
First four parts please
ited Consider the following system at equilibrium where AH = 108 kJ, and K = 1.29 x 10-2, at 600 K: COC1₂ (g) CO(g) + Cl₂ (g) If the temperature on the equilibrium system is suddenly increased: The value of Ke Oincreases Odecreases O remains the same The value of Qc Ols less than Ke Ols greater than K Ols equal to Ke The reaction must Orun in the forward direction to reestablish equilibrium Orun in the reverse direction to reestablish equilibrium O remain in the current position, since it is already at equilibrium The concentration of Cl₂ will O increase O decrease O remain the same 54 $ Submit Ans Show Hint ry Entire Group 9 more group attempts remaining 000 000 F4 R LL F % 5 T Cengage Learning Cengage Technical Support F5 G A 6 MacBook Air Y & 7 ◄◄ F7 U * 8 ► 11 F8 1 9 A F9 10 ) 0 K L F10 P Previous F11 + 11 Next Save
Acetic acid and water react to form hydronium cation and acetate anion, like this: HCH, CO, (aq)+H, o()- H,O"(aq)+CH;co,(aq) Imagine 67. mmol of CH, CO, are added to a flask containing a mixture of HCH, CO,, H, 0, H,0" and CH, CO, at equilibrium, and then answer the following questions. O Zero. What is the rate of the reverse O Greater than zero, but less than the rate of the forward reaction. reaction before any CH,CO, has been added to the flask? O Greater than zero, and equal to the rate of the forward reaction. O Greater than zero, and greater than the rate of the forward reaction. O Zero. What is the rate of the reverse O Greater than zero, but less than the rate of the forward reaction. reaction just after the CH;CO, has O Greater than zero, and equal to the rate of the forward reaction. been added to the flask? O Greater than zero, and greater than the rate of the forward reaction. O Zero. O Greater than zero, but less than the rate of the forward reaction. What is the rate of…