At 448°C the equilibrium constant Kc for the reaction given below is 50. If we start with 100M HI, 5M H2, and 10M of Iz in a 100 L container, H2(g) + I2(g) =2HI§) AH=120 kJ d) Determine the Kc value for the following reaction: HI 1/2 H, + 1/2 ,
At 448°C the equilibrium constant Kc for the reaction given below is 50. If we start with 100M HI, 5M H2, and 10M of Iz in a 100 L container, H2(g) + I2(g) =2HI§) AH=120 kJ d) Determine the Kc value for the following reaction: HI 1/2 H, + 1/2 ,
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![At 448°C the equilibrium constant Kc for the reaction given below is 50. If we start with 100M
HI, 5M H2, and 10M of Iz in a 100 L container,
H2(g) + I2(g) =2HI§) AH=120 kJ
d) Determine the Kc value for the following reaction:
HI
1/2 H, + 1/2 ,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1fdad564-f7d4-4bdb-a01a-3c69f8d57dd4%2F63c8776d-744c-4066-b67d-1648d7609732%2F7o567sf.png&w=3840&q=75)
Transcribed Image Text:At 448°C the equilibrium constant Kc for the reaction given below is 50. If we start with 100M
HI, 5M H2, and 10M of Iz in a 100 L container,
H2(g) + I2(g) =2HI§) AH=120 kJ
d) Determine the Kc value for the following reaction:
HI
1/2 H, + 1/2 ,
Expert Solution
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Step 1
The reaction given is
Hence the equilibrium constant Kc expression for the above reaction is
where [HI] = equilibrium concentration of HI
[H2] = equilibrium concentration of H2
[I2] = equilibrium concentration of I2
Step 2
The reaction for which we have to find equilibrium constant is
Hence the equilibrium constant expression for the above reaction i.e Kc (let's say Kc' ) is
[HI] = equilibrium concentration of HI
[H2] = equilibrium concentration of H2
[I2] = equilibrium concentration of I2
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