3. Water gas is made by reacting hot coke with steam: Cs) + H20 (e) → cO (6 + H2 (e) Whenequilibrium is established at 900K, the partial pressure of CO, H, and H20 are 0.22 atm, 0.63atm, and 0.31 atm,(a) Calculate K at 900K(b) Enough steam is added to raise its partial pressure temporarily to 0.50 atm. What are theequilibrium partial pressures of all gases after equilibrium is re-established

Answered: Water gas is made by reacting hot coke…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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3. Water gas is made by reacting hot coke with steam: Cs) + H20 (e) → cO (6 + H2 (e) When
equilibrium is established at 900K, the partial pressure of CO, H, and H20 are 0.22 atm, 0.63
atm, and 0.31 atm,
(a) Calculate K at 900K
(b) Enough steam is added to raise its partial pressure temporarily to 0.50 atm. What are the
equilibrium partial pressures of all gases after equilibrium is re-established

Expert Solution

Step 1

Equilibrium constant (K_p)

It is the equilibrium constant in terms of partial pressures of reactants and products.

For a reaction;

$\begin{array}{rcl} aA (g) + bB (g) & \leftrightarrow & cC (g) + dD (g) \\ K_{p} & = & \frac{{p_{C}}^{c} {p_{D}}^{d}}{{p_{A}}^{a} {p_{B}}^{b}} \\ p_{C} & = & partial pressure of C \\ p_{D} & = & partial pressure of D \\ p_{A} & = & partial pressure of A \\ p_{B} & = & partial pressure of B \end{array}$

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