The steady-state temperature distribution in a one dimensional wall of thermal conductivity 50 W/m^2.K and thickness 50 mm is observed to be T(C) = a + bx^2, where a = 200 C, b= -3000 C/m^2, and x is in meters. Determine the heat fluxes at x = L Determine the heat fluxes at x = 0 What is the heat generation rate in the wall 15000 W/m^2 0 W/m^2 300000 W/m^3

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
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Author:Kreith, Frank; Manglik, Raj M.
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Chapter7: Forced Convection Inside Tubes And Ducts
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Problem 7.48P
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The steady-state temperature distribution in a
one dimensional wall of thermal conductivity
50 W/m^2.K and thickness 50 mm is observed
to be T(C) = a + bx^2, where a = 200 C, b=
-3000 C/m^2, and x is in meters.
Determine the heat
fluxes at x = L
Determine the heat
fluxes at x = 0
What is the heat
generation rate in the
wall
15000 W/m^2
0 W/m^2
300000 W/m^3
Transcribed Image Text:The steady-state temperature distribution in a one dimensional wall of thermal conductivity 50 W/m^2.K and thickness 50 mm is observed to be T(C) = a + bx^2, where a = 200 C, b= -3000 C/m^2, and x is in meters. Determine the heat fluxes at x = L Determine the heat fluxes at x = 0 What is the heat generation rate in the wall 15000 W/m^2 0 W/m^2 300000 W/m^3
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