The state-space Jordan Canonical Form of the following system is: Y(s) 8-5 U(s) (+1)(+3) Select one: O a. -1 0 0 A = 0 -1 0 B: ... ... ... 0 0 C [4 1.5 1.5], D=0 b. -3 1 0 0 A = 0 -3 0 1 B ... 0 0 -1 C -4 -1.5 1.5], D=0 ○ C. -3 1 0 A = 0 -3 0 1 ,B= ... 0 0 ○ d. C [4 1.5 1.5], D=0 -3 1 0 0 A = 0 -3 0 1 , B: ... ... 0 0 -1 C [4 1.5 1.5], D=0 -4 1 If= x and (0): = then 2(t) is: -4 0 Select one: a. x2(t)=4te2t O b. x2(t) = e2t+2te2t Oc. 2(t)=-4te-21 Od. 2(t) e2-2te-2 =
The state-space Jordan Canonical Form of the following system is: Y(s) 8-5 U(s) (+1)(+3) Select one: O a. -1 0 0 A = 0 -1 0 B: ... ... ... 0 0 C [4 1.5 1.5], D=0 b. -3 1 0 0 A = 0 -3 0 1 B ... 0 0 -1 C -4 -1.5 1.5], D=0 ○ C. -3 1 0 A = 0 -3 0 1 ,B= ... 0 0 ○ d. C [4 1.5 1.5], D=0 -3 1 0 0 A = 0 -3 0 1 , B: ... ... 0 0 -1 C [4 1.5 1.5], D=0 -4 1 If= x and (0): = then 2(t) is: -4 0 Select one: a. x2(t)=4te2t O b. x2(t) = e2t+2te2t Oc. 2(t)=-4te-21 Od. 2(t) e2-2te-2 =
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![The state-space Jordan Canonical Form of the following system is:
Y(s)
8-5
U(s)
(+1)(+3)
Select one:
O a.
-1
0
0
A =
0
-1
0
B:
...
...
...
0
0
C [4 1.5 1.5], D=0
b.
-3 1
0
0
A =
0
-3
0
1
B
...
0
0
-1
C -4
-1.5 1.5], D=0
○ C.
-3 1
0
A =
0
-3
0
1
,B=
...
0
0
○ d.
C [4 1.5 1.5], D=0
-3 1
0
0
A =
0
-3
0
1
, B:
...
...
0
0
-1
C [4 1.5 1.5], D=0
-4 1
If=
x and (0):
=
then 2(t) is:
-4 0
Select one:
a. x2(t)=4te2t
O b. x2(t) = e2t+2te2t
Oc.
2(t)=-4te-21
Od. 2(t) e2-2te-2
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd99b6acb-3c56-46a2-8aaf-762988209417%2Ffe401db8-17c1-41a7-977f-72f0343e0f0d%2Fqinyx9e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The state-space Jordan Canonical Form of the following system is:
Y(s)
8-5
U(s)
(+1)(+3)
Select one:
O a.
-1
0
0
A =
0
-1
0
B:
...
...
...
0
0
C [4 1.5 1.5], D=0
b.
-3 1
0
0
A =
0
-3
0
1
B
...
0
0
-1
C -4
-1.5 1.5], D=0
○ C.
-3 1
0
A =
0
-3
0
1
,B=
...
0
0
○ d.
C [4 1.5 1.5], D=0
-3 1
0
0
A =
0
-3
0
1
, B:
...
...
0
0
-1
C [4 1.5 1.5], D=0
-4 1
If=
x and (0):
=
then 2(t) is:
-4 0
Select one:
a. x2(t)=4te2t
O b. x2(t) = e2t+2te2t
Oc.
2(t)=-4te-21
Od. 2(t) e2-2te-2
=
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