The square footing shown below must be designed to carry a 2400 KN load. Use Terzaghi's bearing capacity formula and factor of safety = 3. Determine the foundation dimension B in the following a. If the water table is well below the foundation level cases: b. If the water table is at the foundation level c. If the water table is at the surface 2400 kN = 32° C= 50 kN/m² Ya = 17.25 kN/m³ 2m 3m

The square footing shown below must be designed to carry a 2400 KN load. Use Terzaghi's bearing capacity formula and factor of safety = 3. Determine the foundation dimension B in the following a. If the water table is well below the foundation level cases: b. If the water table is at the foundation level c. If the water table is at the surface 2400 kN = 32° C= 50 kN/m² Ya = 17.25 kN/m³ 2m 3m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Please correct answer
A 300 mm x 400 mm column is to be supported by 489 m thick square footing @ its center. Service DL= 492 kN, service LL = 917 kN, CC to bar centroid is 90 mm, fc' = 24.32 MPa and fy = 414 MPa. Consider the weight of the footing and soil to be 16.76% of the dead load. SBC = 180 kPa t 300 P 00₺ 300 Note: Present the width (B) in multiples of 100 mm. 400 Determine the required number of 20 mm bars parallel to the critical side.
A continuous footing is to be designed to carry a wall load of 7 kips/ft. The soil shear strength parameters are as follows: Sy = 700 psf and 0 = 0-deg. Foundation Depth, D = 2.5 ft and Soil Unit Weight, y = 110 Ib/ft°. Unit weight of concrete = 150 lb/ft°. Determine the necessary footing width to carry the above column load if a factor of safety of 2.5 is desired. The water table is at great depth and therefore, has no impact on bearing capacity. a) Ultimate Bearing Capacity of the footing (in Ib/ft) using Terzaghi's equation = .(Report to nearest whole number) b) Allowable Bearing Capacity of the footing (in Ib/ft-) using Terzaghi's equation = ...(Report to nearest whole number) c) Footing width (in ft) required = (Report to the nearest two decimals)
A strip footing foundation 1 m wide is constructed in the slope of a hill whose surface inclination is 20°. The soil in the hill is a dense sand, with a unit weight of 19 kN/m3 and an angle of internal friction of 40°. Assume that the D/B ratio is about 1. Applying a factor of safety of 3, determine the wall loading the foundation can carry, per meter of footing length.
A rectangular footing 1.62 x 2.18 in plan. The soil supporting the foundation has a friction angle of 28 degrees and c = 19.03 kPa. The unit weight of soil us 16.10 kN/m3 and the saturated unit weight is 21.94 kN/m3. The bottom of the foundation is at 1.23 meter below the ground and the GWT to be 0.59 meter below the bottom of the footing. Assume the the load is inclined at an angle of 21.04 degrees from the vertical. Compute for the net bearing capacity if the factor of safety is 2.62. Use Meyerhof General Bearing Capacity
F
Use Terzaghi's equation and Terzaghi's Table
The subject is vibration engineering. please make the solution clean and understandable. thanks
The total load on a shallow foundation is 400 kN and the safe bearing capacity of the soilis 200 kN/m2. The area of the footing required, is.
Can't figure this out
Foundation and Retaining Wall Design 3 Decimal Places
A foundation is 3 mx 2 m in plan. Given: Df= 1.5 m, o'= 25°, c'= 70 kN/m². With General Bearing Capacity equation and FS = 3 assmuming general shear failure in soil, determine the net allowable load that the footing can carry. a) NOTE: Due to drought, groundwater level has been lowered down to a depth of 1.5m from the ground surface. b) Net allowable load that the footing can carry using general bearing capacity equation and F.S.=3 assuming general shear failure in soil. c) Ultimate bearing capacity (qu) using prakash and saran theory with eB=0.3m and eL=0.5m. y = 17 kN/m 1 m 1.5 m Groundwater level 3 m x 2 m Yut = 19.5 kN/m