A rectangular footing is to be used to support a 300x400 (*400mm side is parallel to the long dimension of the footing) column loaded with 420 kN dead load and 540 kN live load. One side of the footing is 4.0m. Use effective soil pressure of 70 kPa. f'c=35 MPa and fy=420 MPa. Use minimum steel ratio for longitudinal bars as 0.0018. •Calculate the required thickness of the footing (mm) based on wide beam shear. db=16mm. Size of footing should be multiples of 10mm (Answer: 300) •Calculate the required thickness of the footing based on two-way shear. db=16mm (Answer: 430) • Calculate the required number of 16mm bars along long direction. . Use the governing thickness based on shear requirements. (Answer: 22)

Q: 10

A: f'c=5500 psi (column) f'c=3000 psi Pu=550 k qall=10000 psi fy=60000 psi

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A: Given Data:D.L =…

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A: Consider the free body diagram as;

Q: 5b) (P) = 75 k (shown below). The footing is 3 ft thick and flush with the ground surface. Assume x=…

A: Solution:- The given diagram is shown below,

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A: To design the footing, we will proceed by determining the ultimate bearing capacity of the footing.…

Q: 10. Sieve analysis and hydrometer analysis were performed on a soil sample. The table below…

A:

Q: Question Attached

A: Given:- To find:- Ultimate and Allowable bearing capacities

Q: A 3.44m x 4.49m footing has a 370 mm column at center with the loads P = 597 kN and My=102.7 kN-m…

A:

Q: A foundation is constructed in a soil with the following parameters: c' = 5.0kN/m? y = 18.5 kN/m³ Ø'…

A: The given data is: B=2 m L=3 m C'=5 KN/m2 Q=3000 KN M=300 KN-m calculating eccentricity:…

Q: A strip footing is to be placed 2m below the surface or soil having a cohesion of 40 KPa, unit…

A: Given:- The depth of the footing to be placed = 2 m The cohesion of the soil = 40 kPa The unit…

Q: A continuous footing is to be designed to carry a wall load of 7 kips/ft. The soil shear strength…

A: The given data is: Su=700 psf Wall load, Qa=7 kips/ft Df=2.5 ft FS=2.5 γ=110 lb/ft3

Q: Q.6 A column 12" square with fe' = 5 ksi reinforced with 8 # 10 bars of fy= 60 ksi, supports a…

A: Column size =12"                             Reinforced with 8#10 bars…

Q: A continuous footing with a B = 7.5ft is constructed with a Df of 3ft in a soil with the following…

A: Consider the given data Consider the Tarzaghi Bearing capacity table

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.