Gentlemen, Attached is a screen shot of the solution you have just provided. Original calculation task was:1 kg projectile is launched at 30 m/sec speed 60 degrees from horizontal. Find a speed after 2 sec.If we change mass of projectile from 1 kg to 2 kg then what will we need to do? 3:36LTE+Step 2all 61%The vertical speed of the projectile after 2 secv, = usin 0 – gt= (30 m/s)sin 60° – (9.8 m/s² )(2 s)= 6.38 m/sThe horizontal speed of the projectile a2 seV, = u cos0= (30 m/s)cos 60°= 15 m/sThe speed of the projectile after 2 sec iv= v +v}(15 m/s)' +(6.38 m/s)°=16.3 m/sExplore similar questicII

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Answered: The speed of the projectile after 2 sec…

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The speed of the projectile after 2 sec i V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Gentlemen, Attached is a screen shot of the solution you have just provided.

Original calculation task was:

1 kg projectile is launched at 30 m/sec speed 60 degrees from horizontal. Find a speed after 2 sec.

If we change mass of projectile from 1 kg to 2 kg then what will we need to do?

3:36
LTE+
Step 2
all 61%
The vertical speed of the projectile after 2 sec
v, = usin 0 – gt
= (30 m/s)sin 60° – (9.8 m/s² )(2 s)
= 6.38 m/s
The horizontal speed of the projectile a
2 se
V, = u cos0
= (30 m/s)cos 60°
= 15 m/s
The speed of the projectile after 2 sec i
v= v +v}
(15 m/s)' +(6.38 m/s)°
=16.3 m/s
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