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The speed of the projectile after 2 sec i V

The speed of the projectile after 2 sec i V

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Gentlemen, Attached is a screen shot of the solution you have just provided. 

Original calculation task was:

1 kg projectile is launched at 30 m/sec speed 60 degrees from horizontal. Find a speed after 2 sec.

If we change mass of projectile from 1 kg to 2 kg then what will we need to do?

3:36 LTE+ Step 2 all 61% The vertical speed of the projectile after 2 sec v, = usin 0 – gt = (30 m/s)sin 60° – (9.8 m/s² )(2 s) = 6.38 m/s The horizontal speed of the projectile a 2 se V, = u cos0 = (30 m/s)cos 60° = 15 m/s The speed of the projectile after 2 sec i v= v +v} (15 m/s)' +(6.38 m/s)° =16.3 m/s Explore similar questic II
Transcribed Image Text:3:36 LTE+ Step 2 all 61% The vertical speed of the projectile after 2 sec v, = usin 0 – gt = (30 m/s)sin 60° – (9.8 m/s² )(2 s) = 6.38 m/s The horizontal speed of the projectile a 2 se V, = u cos0 = (30 m/s)cos 60° = 15 m/s The speed of the projectile after 2 sec i v= v +v} (15 m/s)' +(6.38 m/s)° =16.3 m/s Explore similar questic II
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