A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball?
A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball? (Could you please provide a step by step formula?) (This is the Fifth Time I'm asking Bartleby for help with this question, please explain in the diagram in detail please, step by step. ) (For example. for some reason, one of the variables turns from 0.3 into 0.7 m/s, please explain how and why) (Please lable velocities, masses ex. properly as which ones are the initials, finals, which mass belongs to which one.)
![e=1
m2
m2
(0:3) V
Rest
A-fter colli'sion
Before Collision
Inall type of Collisions, linear momentum remains
Conserved. So, m,ui+ m2u2
= m, V, + WaVz
lov+m(0) = -10(0-3)V + mVa
m V2 = 13V
(1)
Vscperadtion
Vapproach
For elastic collision, e=
e=1 =
V2-(-0.3 V)
> V2+0:3V= V
V-0
> Vz = V-0•3V
>
V2 = 0. 7 \V
-(2)
%3D
Foom 1) and (2),
m(0.7)V = 13 V → m= _]3
>So, mass f gtational ball = m = 18·57 Kg.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F020fc153-78b1-4e85-8900-79600afdc2ec%2F8a5f7684-55c9-4433-bdbd-217e29160ac3%2Fxuygwwh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:e=1
m2
m2
(0:3) V
Rest
A-fter colli'sion
Before Collision
Inall type of Collisions, linear momentum remains
Conserved. So, m,ui+ m2u2
= m, V, + WaVz
lov+m(0) = -10(0-3)V + mVa
m V2 = 13V
(1)
Vscperadtion
Vapproach
For elastic collision, e=
e=1 =
V2-(-0.3 V)
> V2+0:3V= V
V-0
> Vz = V-0•3V
>
V2 = 0. 7 \V
-(2)
%3D
Foom 1) and (2),
m(0.7)V = 13 V → m= _]3
>So, mass f gtational ball = m = 18·57 Kg.
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