2. Knight P11.8 A 2.00 kg object is moving to the right with a speed of 1.00 m/s when it encounters the force shown below. (a) What impulse does the force exert? (b) What is the object's speed and direction after the force ends? F. (N) 2 0 -2 1.0 s t(s) Answers to one significant figure. These are given so you
2. Knight P11.8 A 2.00 kg object is moving to the right with a speed of 1.00 m/s when it encounters the force shown below. (a) What impulse does the force exert? (b) What is the object's speed and direction after the force ends? F. (N) 2 0 -2 1.0 s t(s) Answers to one significant figure. These are given so you
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![2. Knight P11.8 A 2.00 kg object is moving to the
right with a speed of 1.00 m/s when it encounters
the force shown below.
(a) What impulse does the force exert?
(b) What is the object's speed and direction after
the force ends?
Fx (N)
2
0
-2
1.0 s
-t (s)
Answers to one significant figure. These are given so you](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcef3f1b2-56cd-4f45-949e-fc7a38ef994c%2Ff2f066f0-940e-4b38-9fbf-eb42477416bf%2Fpz8pb6c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Knight P11.8 A 2.00 kg object is moving to the
right with a speed of 1.00 m/s when it encounters
the force shown below.
(a) What impulse does the force exert?
(b) What is the object's speed and direction after
the force ends?
Fx (N)
2
0
-2
1.0 s
-t (s)
Answers to one significant figure. These are given so you
![Useful information
gravitational acceleration g = 9.8 m/s²
Gravity
Power
Momentum
Newton's 2nd law
Impulse
ΔΕsys
P =
At
P = F cos 0 Vx
Fg = -mg
Ug = mgy
Ap=
pt f
p = mi
F =
AP
个
desys
dt
18
F
F(t) dt
→ area under the F-t graph](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcef3f1b2-56cd-4f45-949e-fc7a38ef994c%2Ff2f066f0-940e-4b38-9fbf-eb42477416bf%2Fxzcb4vm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Useful information
gravitational acceleration g = 9.8 m/s²
Gravity
Power
Momentum
Newton's 2nd law
Impulse
ΔΕsys
P =
At
P = F cos 0 Vx
Fg = -mg
Ug = mgy
Ap=
pt f
p = mi
F =
AP
个
desys
dt
18
F
F(t) dt
→ area under the F-t graph
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