The solubility of the K3[Fe(C2O4)3]. 3H2O product at 0°C is 4.7 g per 100 g water. Given this, calculate the maximum percent yield of product for your own reactant quantities. Volume of FeCl3 = 5 ml Volume of distilled water used = 10 mL Concentration of FeCl3 = 1.8 M Mass of product K3[Fe(C2O4)3]. 3H2O after the reaction is = 2 grams. I found my percent yield of K3[Fe(C2O4)3]. 3H2O to be 40.10% Could you also explain why you used the numbers you used?
The solubility of the K3[Fe(C2O4)3]. 3H2O product at 0°C is 4.7 g per 100 g water. Given this, calculate the maximum percent yield of product for your own reactant quantities. Volume of FeCl3 = 5 ml Volume of distilled water used = 10 mL Concentration of FeCl3 = 1.8 M Mass of product K3[Fe(C2O4)3]. 3H2O after the reaction is = 2 grams. I found my percent yield of K3[Fe(C2O4)3]. 3H2O to be 40.10% Could you also explain why you used the numbers you used?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The solubility of the K3[Fe(C2O4)3]. 3H2O product at 0°C is 4.7 g per 100 g water. Given this, calculate the maximum percent yield of product for your own reactant quantities.
Volume of FeCl3 = 5 ml
Volume of distilled water used = 10 mL
Concentration of FeCl3 = 1.8 M
Mass of product K3[Fe(C2O4)3]. 3H2O after the reaction is = 2 grams. I found my percent yield of K3[Fe(C2O4)3]. 3H2O to be 40.10%
Could you also explain why you used the numbers you used?
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