1. The solubility of magnesium hydroxide (Mg(OH)2) is approximately 3.7 x10-5 M at room temperature.

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**Transcription for Educational Website: Chemistry Concepts**

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**Exercise: Solubility and Thermodynamics of Magnesium Hydroxide**

**1. Solubility of Magnesium Hydroxide (Mg(OH)₂):**

- The solubility of magnesium hydroxide (Mg(OH)₂) is approximately \(3.7 \times 10^{-5}\) M at room temperature.

  a. **Dissolution Reaction:**
     - Write the dissolution reaction for magnesium hydroxide, including state symbols.

  b. **Solubility Product Constant (K\(_{sp}\)):**
     - Calculate the solubility product constant (K\(_{sp}\)) for magnesium hydroxide at room temperature.

  c. **Mass in Solution:**
     - How many grams of magnesium hydroxide are present in 1.0 L of a saturated solution at room temperature?

**2. Thermodynamic Analysis Using Graphical Data:**

- A plot of \( \ln K \) vs. \( \frac{1}{T} \) gives a slope of \(-2980 \, \text{K}\) and an intercept of \(-10.6\).
  
  - Calculate \( \Delta H^{\circ} \) in kJ/mol and \( \Delta S^{\circ} \) in J\(\cdot\)K\(^{-1}\)\(\cdot\)mol\(^{-1}\).
  
  - **Hint:** What is the equation for this line in terms of \( K \), \( T \), \( \Delta H^{\circ} \), and \( \Delta S^{\circ} \)?

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*Edited: 8/12/2019*  
*Page 2*
Transcribed Image Text:**Transcription for Educational Website: Chemistry Concepts** --- **Exercise: Solubility and Thermodynamics of Magnesium Hydroxide** **1. Solubility of Magnesium Hydroxide (Mg(OH)₂):** - The solubility of magnesium hydroxide (Mg(OH)₂) is approximately \(3.7 \times 10^{-5}\) M at room temperature. a. **Dissolution Reaction:** - Write the dissolution reaction for magnesium hydroxide, including state symbols. b. **Solubility Product Constant (K\(_{sp}\)):** - Calculate the solubility product constant (K\(_{sp}\)) for magnesium hydroxide at room temperature. c. **Mass in Solution:** - How many grams of magnesium hydroxide are present in 1.0 L of a saturated solution at room temperature? **2. Thermodynamic Analysis Using Graphical Data:** - A plot of \( \ln K \) vs. \( \frac{1}{T} \) gives a slope of \(-2980 \, \text{K}\) and an intercept of \(-10.6\). - Calculate \( \Delta H^{\circ} \) in kJ/mol and \( \Delta S^{\circ} \) in J\(\cdot\)K\(^{-1}\)\(\cdot\)mol\(^{-1}\). - **Hint:** What is the equation for this line in terms of \( K \), \( T \), \( \Delta H^{\circ} \), and \( \Delta S^{\circ} \)? --- *Edited: 8/12/2019* *Page 2*
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