The solubility of KCI in H20 is 344 g/L. An aqueous solution of KCI that is 250 g/L would be described a v saturated unsaturated supersaturated
The solubility of KCI in H20 is 344 g/L. An aqueous solution of KCI that is 250 g/L would be described a v saturated unsaturated supersaturated
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:**Understanding Solution Saturation Levels**
**The solubility of KCl in H₂O is 344 g/L. An aqueous solution of KCl that is 250 g/L would be described as:**
- saturated
- unsaturated
- supersaturated
In the image, there's also a dropdown menu with options for selecting the solution saturation level. The options are:
1. **saturated**
2. **unsaturated**
3. **supersaturated**
For an educational perspective: if the solubility of KCl (potassium chloride) in water (H₂O) at a particular temperature is 344 grams per liter (g/L), and we have a solution where the concentration of KCl is 250 g/L, this would imply it is **unsaturated** because the concentration is less than its maximum solubility.
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