Determine the freezing point (in °C) of a solution that contains 204 g of CsH1206 dissolved in 234 mL of acetic acid (density = 1.05 g/mL). Pure acetic acid has a freezing point of 16.6°C and a K = 3.90°C/m.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
**Title: Determining the Freezing Point of a Solution: A Practical Application**

**Objective:**
Learn how to determine the freezing point of a solution given specific solute and solvent properties.

**Problem Statement:**
Determine the freezing point (in °C) of a solution that contains 204 g of \( \text{C}_6\text{H}_{12}\text{O}_6 \) dissolved in 234 mL of acetic acid (density = 1.05 g/mL). Pure acetic acid has a freezing point of 16.6°C and a \( K_f \) (cryoscopic constant) = 3.90°C·kg/mol.

**Solution Approach:**

1. **Identify the Given Data:**
   - Mass of solute (Glucose, \( \text{C}_6\text{H}_{12}\text{O}_6 \)): \( m = 204 \) g
   - Volume of solvent (Acetic Acid): \( V = 234 \) mL
   - Density of solvent: \( \rho = 1.05 \) g/mL
   - Freezing point of pure acetic acid: \( T_f^0 = 16.6 \)°C
   - Cryoscopic constant (\( K_f \)): 3.90°C·kg/mol

2. **Calculate Moles of Solute:**
   - Molar mass of glucose (\( \text{C}_6\text{H}_{12}\text{O}_6 \)): 180 g/mol
   \[
   \text{Moles of glucose} = \frac{\text{mass}}{\text{molar mass}} = \frac{204 \text{ g}}{180 \text{ g/mol}} = 1.133 \text{ mol}
   \]

3. **Calculate Mass of Solvent:**
   - Convert volume to mass using the density:
   \[
   \text{Mass of acetic acid} = \text{density} \times \text{volume} = 1.05 \frac{\text{g}}{\text{mL}} \times 234 \text{ mL} = 245.7 \text{ g} = 0.2457 \text{ kg}
   \]

4. **Determine Molality of the Solution:**
   - Molality (\( m \
Transcribed Image Text:**Title: Determining the Freezing Point of a Solution: A Practical Application** **Objective:** Learn how to determine the freezing point of a solution given specific solute and solvent properties. **Problem Statement:** Determine the freezing point (in °C) of a solution that contains 204 g of \( \text{C}_6\text{H}_{12}\text{O}_6 \) dissolved in 234 mL of acetic acid (density = 1.05 g/mL). Pure acetic acid has a freezing point of 16.6°C and a \( K_f \) (cryoscopic constant) = 3.90°C·kg/mol. **Solution Approach:** 1. **Identify the Given Data:** - Mass of solute (Glucose, \( \text{C}_6\text{H}_{12}\text{O}_6 \)): \( m = 204 \) g - Volume of solvent (Acetic Acid): \( V = 234 \) mL - Density of solvent: \( \rho = 1.05 \) g/mL - Freezing point of pure acetic acid: \( T_f^0 = 16.6 \)°C - Cryoscopic constant (\( K_f \)): 3.90°C·kg/mol 2. **Calculate Moles of Solute:** - Molar mass of glucose (\( \text{C}_6\text{H}_{12}\text{O}_6 \)): 180 g/mol \[ \text{Moles of glucose} = \frac{\text{mass}}{\text{molar mass}} = \frac{204 \text{ g}}{180 \text{ g/mol}} = 1.133 \text{ mol} \] 3. **Calculate Mass of Solvent:** - Convert volume to mass using the density: \[ \text{Mass of acetic acid} = \text{density} \times \text{volume} = 1.05 \frac{\text{g}}{\text{mL}} \times 234 \text{ mL} = 245.7 \text{ g} = 0.2457 \text{ kg} \] 4. **Determine Molality of the Solution:** - Molality (\( m \
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Solutions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY