The boiling point of water is 100.0°C at 1 atmosphere. How many grams of barium acetate (255.4 g/mol), must be dissolved in 204.0 grams of water to raise the boiling point by 0.350 °C? Refer to the table for the necessary boiling or freezing point constant. Solvent Kb (°C/m) Kf(°C/m) Water H₂O 0.512 Ethanol CH3 CH₂OH 1.22 Chloroform CHC13 3.67 Benzene C6H6 2.53 Diethyl ether CH3 CH₂ OCH₂ CH3 2.02 g barium acetate Mass= Formula 1.86 1.99 5.12
The boiling point of water is 100.0°C at 1 atmosphere. How many grams of barium acetate (255.4 g/mol), must be dissolved in 204.0 grams of water to raise the boiling point by 0.350 °C? Refer to the table for the necessary boiling or freezing point constant. Solvent Kb (°C/m) Kf(°C/m) Water H₂O 0.512 Ethanol CH3 CH₂OH 1.22 Chloroform CHC13 3.67 Benzene C6H6 2.53 Diethyl ether CH3 CH₂ OCH₂ CH3 2.02 g barium acetate Mass= Formula 1.86 1.99 5.12
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Boiling Point Elevation Calculation**
The boiling point of water is 100.0°C at 1 atmosphere.
**Problem Statement:**
How many grams of barium acetate (255.4 g/mol) must be dissolved in 204.0 grams of water to raise the boiling point by 0.350 °C?
**Reference Table: Boiling and Freezing Point Constants**
| Solvent | Formula | \( K_b \) (°C/m) | \( K_f \) (°C/m) |
|--------------|-----------------|------------------|-------------------|
| Water | \( H_2O \) | 0.512 | 1.86 |
| Ethanol | \( CH_3CH_2OH \) | 1.22 | 1.99 |
| Chloroform | \( CHCl_3 \) | 3.67 | - |
| Benzene | \( C_6H_6 \) | 2.53 | 5.12 |
| Diethyl ether| \( CH_3CH_2OCH_2CH_3 \) | 2.02 | - |
**Calculation:**
\[ \text{Mass} = \text{g barium acetate} \]
Use the values from the table and the given information to solve for the mass of barium acetate required.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F15cd763b-5763-4f34-ac90-fb3a4d78f352%2F17af3e98-5cab-4e2d-931f-8a70f37d3dbf%2Ft5wqhb_processed.png&w=3840&q=75)
Transcribed Image Text:**Boiling Point Elevation Calculation**
The boiling point of water is 100.0°C at 1 atmosphere.
**Problem Statement:**
How many grams of barium acetate (255.4 g/mol) must be dissolved in 204.0 grams of water to raise the boiling point by 0.350 °C?
**Reference Table: Boiling and Freezing Point Constants**
| Solvent | Formula | \( K_b \) (°C/m) | \( K_f \) (°C/m) |
|--------------|-----------------|------------------|-------------------|
| Water | \( H_2O \) | 0.512 | 1.86 |
| Ethanol | \( CH_3CH_2OH \) | 1.22 | 1.99 |
| Chloroform | \( CHCl_3 \) | 3.67 | - |
| Benzene | \( C_6H_6 \) | 2.53 | 5.12 |
| Diethyl ether| \( CH_3CH_2OCH_2CH_3 \) | 2.02 | - |
**Calculation:**
\[ \text{Mass} = \text{g barium acetate} \]
Use the values from the table and the given information to solve for the mass of barium acetate required.
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