The boiling point of water is 100.0°C at 1 atmosphere. How many grams of barium acetate (255.4 g/mol), must be dissolved in 204.0 grams of water to raise the boiling point by 0.350 °C? Refer to the table for the necessary boiling or freezing point constant. Solvent Kb (°C/m) Kf(°C/m) Water H₂O 0.512 Ethanol CH3 CH₂OH 1.22 Chloroform CHC13 3.67 Benzene C6H6 2.53 Diethyl ether CH3 CH₂ OCH₂ CH3 2.02 g barium acetate Mass= Formula 1.86 1.99 5.12

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**Boiling Point Elevation Calculation**

The boiling point of water is 100.0°C at 1 atmosphere.

**Problem Statement:**

How many grams of barium acetate (255.4 g/mol) must be dissolved in 204.0 grams of water to raise the boiling point by 0.350 °C?

**Reference Table: Boiling and Freezing Point Constants**

| Solvent      | Formula         | \( K_b \) (°C/m) | \( K_f \) (°C/m) |
|--------------|-----------------|------------------|-------------------|
| Water        | \( H_2O \)      | 0.512            | 1.86              |
| Ethanol      | \( CH_3CH_2OH \) | 1.22             | 1.99              |
| Chloroform   | \( CHCl_3 \)    | 3.67             | -                 |
| Benzene      | \( C_6H_6 \)    | 2.53             | 5.12              |
| Diethyl ether| \( CH_3CH_2OCH_2CH_3 \) | 2.02  | -                 |

**Calculation:**

\[ \text{Mass} = \text{g barium acetate} \]

Use the values from the table and the given information to solve for the mass of barium acetate required.
Transcribed Image Text:**Boiling Point Elevation Calculation** The boiling point of water is 100.0°C at 1 atmosphere. **Problem Statement:** How many grams of barium acetate (255.4 g/mol) must be dissolved in 204.0 grams of water to raise the boiling point by 0.350 °C? **Reference Table: Boiling and Freezing Point Constants** | Solvent | Formula | \( K_b \) (°C/m) | \( K_f \) (°C/m) | |--------------|-----------------|------------------|-------------------| | Water | \( H_2O \) | 0.512 | 1.86 | | Ethanol | \( CH_3CH_2OH \) | 1.22 | 1.99 | | Chloroform | \( CHCl_3 \) | 3.67 | - | | Benzene | \( C_6H_6 \) | 2.53 | 5.12 | | Diethyl ether| \( CH_3CH_2OCH_2CH_3 \) | 2.02 | - | **Calculation:** \[ \text{Mass} = \text{g barium acetate} \] Use the values from the table and the given information to solve for the mass of barium acetate required.
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