The solubility of ammonium formate, NH4HCO2, in 100. g of water is 102 g at 0 °C and 546 g at 80 °C. A solution is prepared by dissolving NH4HCO₂ in 235 g of water until no more will dissolve at 80 °C. The solution is then cooled to 0 °C. What mass of NH4HCO2 precipitates? (Assume that no water evaporates and that the solution is not supersaturated.) Mass= 9
The solubility of ammonium formate, NH4HCO2, in 100. g of water is 102 g at 0 °C and 546 g at 80 °C. A solution is prepared by dissolving NH4HCO₂ in 235 g of water until no more will dissolve at 80 °C. The solution is then cooled to 0 °C. What mass of NH4HCO2 precipitates? (Assume that no water evaporates and that the solution is not supersaturated.) Mass= 9
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![**Solubility of Ammonium Formate**
The solubility of ammonium formate (\( \text{NH}_4\text{HCO}_2 \)) in 100 grams of water is as follows:
- 102 grams at 0°C
- 546 grams at 80°C
A solution is prepared by dissolving \(\text{NH}_4\text{HCO}_2\) in 235 grams of water until no more will dissolve at 80°C. The solution is then cooled to 0°C. Determine the mass of \(\text{NH}_4\text{HCO}_2\) that precipitates under these conditions.
**Assumptions:**
- No water evaporates
- The solution is not supersaturated
**Calculate the Precipitation Mass:**
Mass = [Input field for the answer]
**Options:**
- Submit Answer
- Try Another Version (2 attempts remaining)
This activity involves calculating how much of the solute will precipitate out of solution as temperature decreases from 80°C to 0°C, based on changes in solubility.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F61a624e8-9805-4882-bd7c-8b439f9ba0a9%2F36877868-7b85-47b6-b770-64864eb28dca%2Fybhbicp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Solubility of Ammonium Formate**
The solubility of ammonium formate (\( \text{NH}_4\text{HCO}_2 \)) in 100 grams of water is as follows:
- 102 grams at 0°C
- 546 grams at 80°C
A solution is prepared by dissolving \(\text{NH}_4\text{HCO}_2\) in 235 grams of water until no more will dissolve at 80°C. The solution is then cooled to 0°C. Determine the mass of \(\text{NH}_4\text{HCO}_2\) that precipitates under these conditions.
**Assumptions:**
- No water evaporates
- The solution is not supersaturated
**Calculate the Precipitation Mass:**
Mass = [Input field for the answer]
**Options:**
- Submit Answer
- Try Another Version (2 attempts remaining)
This activity involves calculating how much of the solute will precipitate out of solution as temperature decreases from 80°C to 0°C, based on changes in solubility.
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