The soil has cross sectional area of flow of 1 ft2 and a hydraulic conductivity of 1.45 x 104 ft/sec. Calculate the rate of flow. Supply SE 7.6 ft³/day 6.3 ft³/day 3.1 ft³/day 4.8 ft³/day 1 ft Soil 2 ft Outflow, Q

The soil has cross sectional area of flow of 1 ft2 and a hydraulic conductivity of 1.45 x 104 ft/sec. Calculate the rate of flow. Supply SE 7.6 ft³/day 6.3 ft³/day 3.1 ft³/day 4.8 ft³/day 1 ft Soil 2 ft Outflow, Q

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Field applications of hydraulic conductivity

Hydraulic conductivity is one of the hydraulic properties of soil defined as a measurement of the ability of a porous medium to permit water movement or fluid flow through it. It is denoted by the letter K. It is influenced by the density and viscosity of the fluid. It is also called permeability. Hydraulic conductivity is defined as the ratio of velocity to the hydraulic gradient. The different methods used to determine the hydraulic conductivity are laboratory methods (constant head permeability tests and falling head tests), in-situ field methods (pumping in and pumping out tests), small scale field tests (infiltration tests and slug tests), and indirect methods such as estimation from grain size, consolidation test data, and horizontal capillary test. The pedotransfer function (PTF) method is a specific empirical estimating approach employed in the soil sciences is also used to determine the hydraulic conductivity of the soil.

Question

The soil has cross sectional area of flow of 1 ft² and a hydraulic conductivity of 1.45
x 104 ft/sec. Calculate the rate of flow.
Supply
7.6 ft³/day
6.3 ft³/day
3.1 ft³/day
4.8 ft³/day
1 ft
Soil
2 ft
H
Outflow, Q

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