Determine the time of concentration for use in the NRCS method for a drainage basin located in Hardin County, Ohio having the hydraulic path described below: Overland Average Grass L = 100’ S = 1.6% n = 0.24 Shallow Concentrated L = 680’ S = 3.2% Stream Flow L = 2950’ S = 0.61% Cross Section o B = 12’ o T = 20’ o y = 4’ o n = 0.035 COUNTY 2-yr ; 5-yr ; 10-yr ; 25-yr ; 50-yr ; 100-yr HARDIN 2.5 ; 3.0 ; 3.5 ; 4.2 ; 4.7 ; 5.3
Determine the time of concentration for use in the NRCS method for a drainage basin located in Hardin County, Ohio having the hydraulic path described below: Overland Average Grass L = 100’ S = 1.6% n = 0.24 Shallow Concentrated L = 680’ S = 3.2% Stream Flow L = 2950’ S = 0.61% Cross Section o B = 12’ o T = 20’ o y = 4’ o n = 0.035 COUNTY 2-yr ; 5-yr ; 10-yr ; 25-yr ; 50-yr ; 100-yr HARDIN 2.5 ; 3.0 ; 3.5 ; 4.2 ; 4.7 ; 5.3
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Determine the time of concentration for use in the NRCS method for a drainage basin located in
Hardin County, Ohio having the hydraulic path described below:
Overland
Average Grass
L = 100’
S = 1.6%
n = 0.24
Shallow Concentrated
L = 680’
S = 3.2%
Stream Flow
L = 2950’
S = 0.61%
Cross Section
o B = 12’
o T = 20’
o y = 4’
o n = 0.035
COUNTY 2-yr ; 5-yr ; 10-yr ; 25-yr ; 50-yr ; 100-yr
HARDIN 2.5 ; 3.0 ; 3.5 ; 4.2 ; 4.7 ; 5.3

Transcribed Image Text:0.40
45
200
B
60 -
-
1
1
1
1
1
-2
A
PER
10
50
∞
6
4
Time of concentration (tc), hours
.8
1
9°
b
.2
I'
Unit peak discharge (qu), csm/in
FIGURE D-5. (CHART 3) Unit peak discharge (qu) for NRCS type II rainfall distribution. (Courtesy of
Soil Conservation Service, Technical Release 55.)
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