Revision for examswant ot make sure i am doing it right Calculate the discharge for a flow depth of 0.85 m in a trapezoidal openchannel with bottom width 1 m and side slopes of 1 vertical: 2 horizontals. Thebed slope is 0.5 m/ 100 m and Manning's n value is 0.035.The flow from part (a) enters a 1.2 m diameter stormwater sewer laid at the samegrade as the bed of the open channel, for which the pipe-flow chart, Appendix 2applies.Use Appendix 3 to obtain the depth of uniform flow in the sewer and its meanvelocity. Show all workings and calculations. Appendix 3: Partial or Hydraulic Elements graph.Relative depth of flow1.00.90.80.70.60.50.40.30.20.100DischargeHydraulic radius.VelocityArea0.10.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3Hydraulic elements in terms of hydraulic elements for full section:A, and RR fullYfull full A fullAppendix 2: The pipe flow/Wallingford graph.Velocity V (m/s)181614121-009080-70-60-5040:30:20-180-140-120-100-090:000:070.06Discharge Q (I/s) for pipes flowing full00Diameter D (m)± 2203206000²0.030-020-010.008Water at 15°C0.00080.00040-000300002Hydraulic gradient 100S (m/100m)

Calculate the discharge for a flow depth of 0.85 m in a trapezoidal open channel with bottom width 1 m and side slopes of 1 vertical: 2 horizontals. The bed slope is 0.5 m/ 100 m and Manning's n value is 0.035. The flow from part (a) enters a 1.2 m diameter stormwater sewer laid at the same grade as the bed of the open channel, for which the pipe-flow chart, Appendix 2 applies. Use Appendix 3 to obtain the depth of uniform flow in the sewer and its mean velocity. Show all workings and calculations.

Calculate the discharge for a flow depth of 0.85 m in a trapezoidal open channel with bottom width 1 m and side slopes of 1 vertical: 2 horizontals. The bed slope is 0.5 m/ 100 m and Manning's n value is 0.035. The flow from part (a) enters a 1.2 m diameter stormwater sewer laid at the same grade as the bed of the open channel, for which the pipe-flow chart, Appendix 2 applies. Use Appendix 3 to obtain the depth of uniform flow in the sewer and its mean velocity. Show all workings and calculations.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.

Question

Revision for exams

want ot make sure i am doing it right

Calculate the discharge for a flow depth of 0.85 m in a trapezoidal open
channel with bottom width 1 m and side slopes of 1 vertical: 2 horizontals. The
bed slope is 0.5 m/ 100 m and Manning's n value is 0.035.
The flow from part (a) enters a 1.2 m diameter stormwater sewer laid at the same
grade as the bed of the open channel, for which the pipe-flow chart, Appendix 2
applies.
Use Appendix 3 to obtain the depth of uniform flow in the sewer and its mean
velocity. Show all workings and calculations.

Appendix 3: Partial or Hydraulic Elements graph.
Relative depth of flow
1.0
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0
0
Discharge
Hydraulic radius.
Velocity
Area
0.1
0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3
Hydraulic elements in terms of hydraulic elements for full section:
A, and R
R full
Yfull full A full
Appendix 2: The pipe flow/Wallingford graph.
Velocity V (m/s)
18
16
14
12
1-0
09
08
0-7
0-6
0-5
04
0:3
0:2
0-18
0-14
0-12
0-10
0-09
0:00
0:07
0.06
Discharge Q (I/s) for pipes flowing full
00
Diameter D (m)
± 22
03
20
600
0²
0.03
0-02
0-01
0.008
Water at 15°C
0.0008
0.0004
0-0003
00002
Hydraulic gradient 100S (m/100m)

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