The small piston of a hydraulic lift (see figure below) has a cross-sectional area of 2.90 cm2, and its large piston has a cross-sectional area of 204 cm2. What downward force of magnitude F, must be applied to the small piston for the lift to raise a load whose weight is = 14.8 kN?

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Chapter1: Units, Trigonometry. And Vectors
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The small piston of a hydraulic lift (see figure below) has a cross-sectional area of 2.90 cm2, and its large piston has a cross-sectional area of 204 cm2. What downward
force of magnitude F, must be applied to the small piston for the lift to raise a load whose weight is F = 14.8 kN?
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Transcribed Image Text:The small piston of a hydraulic lift (see figure below) has a cross-sectional area of 2.90 cm2, and its large piston has a cross-sectional area of 204 cm2. What downward force of magnitude F, must be applied to the small piston for the lift to raise a load whose weight is F = 14.8 kN? Need Help? Watch It Read It
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