The diagram illustrates the principle of hydraulic systems, demonstrating how a small force applied to a smaller piston can be used to lift a larger load using a larger piston.**Description:**- **Left Side:** A small piston is subjected to a force \( F_1 \). The area of this piston is \( A_1 \), creating a pressure \( p = \frac{F_1}{A_1} \).- **Right Side:** The larger piston has an area \( A_2 \) and experiences a force \( F_2 \).**Key Concept:**- **Pressure Equilibrium:** The pressure \( p \) is constant throughout the fluid and is equal at points with the same height. Consequently, the pressure on both pistons is the same.- **Force Relationship:** Because \( p = \frac{F_1}{A_1} = \frac{F_2}{A_2} \), a larger force \( F_2 \) can be achieved by increasing the area \( A_2 \) of the larger piston, allowing it to lift heavier objects, such as a car shown on the larger piston.This figure effectively demonstrates Pascal's Principle, which is fundamental in hydraulic lift systems. For the hydraulic lift shown in Figure 1, what must be the ratio of the diameter of the vessel at the car to the diameter of the vessel where the force \( F_1 \) is applied so that a 1420 kg car can be lifted with a force \( F_1 \) of just 110 N?The diagram accompanying this question is not visible here. However, it would typically illustrate a hydraulic system with labeled components showing where forces are applied and how they relate to each other according to Pascal's Principle. The box underneath the text includes input options for mathematical symbols, indicating that the format allows for equation entry.\[\frac{D_{\text{car}}}{D_{F_1}} = \text{[input field]}\]

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Answered: A small force is applied to a small…

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A small force is applied to a small piston. Because the pressure p is the same at all points at a given height in the fluid .. F2 pA2 ... a piston of larger area at the same height experiences a larger force.