The skiing duo of Brian (81 kg ) and Ashley (54 kg ) is always a crowd pleaser. In one routine, Brian, wearing wood skis, starts at the top of a 290-m-long, 20° slope. Ashley waits for him halfway down. As he skis past, she leaps into his arms and he carries her the rest of the way down. Hint Use coefficient of kinetic friction from Table 6.1 in the textbook. Part A What is their speed at the bottom of the slope? Express your answer to two significant figures and include the appropriate units.

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A Model of Friction
These ideas can be summarized in a model of friction:
TABLE 6.1 Coefficients of friction
Static Kinetic Rolling
Static: f, < (µzn, direction as necessary to prevent motion)
Kinetic: F
Rolling: ,
Materials
= (uk n, direction opposite the motion)
= (µ,n, direction opposite the motion)
(6.15)
Rubber on
concrete
1.00
0.80
0.02
Steel on steel
(dry)
0.80
0.60
0.002
Here “motion" means “motion relative to the surface." The maximum value of static
Steel on steel
friction f. max = µ̟n occurs at the point where the object slips and begins to move.
(lubricated)
0.10
0.05
NOTE > Equations 6.15 are a “model" of friction, not a “law" of friction. These
equations-a simplification of reality-provide a reasonably accurate, but not per-
fect, description of how friction forces act. They are not a “law of nature" on a level
Wood on wood
0.50
0.20
Wood on snow
0.12
0.06
Ice on ice
0.10
0.03
with Newton's laws. «
Transcribed Image Text:A Model of Friction These ideas can be summarized in a model of friction: TABLE 6.1 Coefficients of friction Static Kinetic Rolling Static: f, < (µzn, direction as necessary to prevent motion) Kinetic: F Rolling: , Materials = (uk n, direction opposite the motion) = (µ,n, direction opposite the motion) (6.15) Rubber on concrete 1.00 0.80 0.02 Steel on steel (dry) 0.80 0.60 0.002 Here “motion" means “motion relative to the surface." The maximum value of static Steel on steel friction f. max = µ̟n occurs at the point where the object slips and begins to move. (lubricated) 0.10 0.05 NOTE > Equations 6.15 are a “model" of friction, not a “law" of friction. These equations-a simplification of reality-provide a reasonably accurate, but not per- fect, description of how friction forces act. They are not a “law of nature" on a level Wood on wood 0.50 0.20 Wood on snow 0.12 0.06 Ice on ice 0.10 0.03 with Newton's laws. «
The skiing duo of Brian (81 kg ) and Ashley (54 kg ) is always a crowd pleaser. In one
routine, Brian, wearing wood skis, starts at the top of a 290-m-long, 20° slope. Ashley
waits for him halfway down. As he skis past, she leaps into his arms and he carries
her the rest of the way down. Hint. Use coefficient of kinetic friction from Table 6.1 in
the textbook.
Part A
What is their speed at the bottom of the slope?
Express your answer to two significant figures and include the appropriate units.
?
v =
Value
Units
Submit
Request Answer
Transcribed Image Text:The skiing duo of Brian (81 kg ) and Ashley (54 kg ) is always a crowd pleaser. In one routine, Brian, wearing wood skis, starts at the top of a 290-m-long, 20° slope. Ashley waits for him halfway down. As he skis past, she leaps into his arms and he carries her the rest of the way down. Hint. Use coefficient of kinetic friction from Table 6.1 in the textbook. Part A What is their speed at the bottom of the slope? Express your answer to two significant figures and include the appropriate units. ? v = Value Units Submit Request Answer
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