A 62.0 kg skier is moving at 6.10 m/s on a frictionless, horizontal, snow-covered plateau when she encounters a rough patch 4.50 m long. The coefficient of kinetic friction between this patch and her skis is 0.300. After crossing the rough patch and returning to friction-free snow, she skis down an icy, frictionless hill 2.50 m high. Part A How fast is the skier moving when she gets to the bottom of the hill? Express your answer with the appropriate units. 1/₂ = Submit ▾ Part B Value Request Answer Units ? How much internal energy was generated in crossing the rough patch? Express your answer with the appropriate units.
A 62.0 kg skier is moving at 6.10 m/s on a frictionless, horizontal, snow-covered plateau when she encounters a rough patch 4.50 m long. The coefficient of kinetic friction between this patch and her skis is 0.300. After crossing the rough patch and returning to friction-free snow, she skis down an icy, frictionless hill 2.50 m high. Part A How fast is the skier moving when she gets to the bottom of the hill? Express your answer with the appropriate units. 1/₂ = Submit ▾ Part B Value Request Answer Units ? How much internal energy was generated in crossing the rough patch? Express your answer with the appropriate units.
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Transcribed Image Text:A 62.0 kg skier is moving at 6.10 m/s on a
frictionless, horizontal, snow-covered plateau when
she encounters a rough patch 4.50 m long. The
coefficient of kinetic friction between this patch and
her skis is 0.300. After crossing the rough patch
and returning to friction-free snow, she skis down
an icy, frictionless hill 2.50 m high.
▼
Part A
How fast is the skier moving when she gets to the bottom of the hill?
Express your answer with the appropriate units.
1/2 =
Submit
▾ Part B
HA
Value
Request Answer
Units
?
How much internal energy was generated in crossing the rough patch?
Express your answer with the appropriate units.
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Step 1: Know the concepts to be used:
VIEWStep 2: Derive the expression for the total initial energy of the system:
VIEWStep 3: Derive the expression for the total final energy of the system:
VIEWStep 4: Derive the expression for the final speed of the person at the bottom of mountain:
VIEWStep 5: Part (A) Calculate the final speed of the person
VIEWStep 6: Part (B) Calculate the internal energy produced when the person crosses rough surface:
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