Part A You want to naila 1.9 kg board to the wall of a barn, as shown below. To position the board before naling, you push it against the wall with a horizontal force F to keep it from sliding to the ground. The coefficient.of static friction between the board and the wall is 0.64 The least force you can apply and still hold the board in place is (enter your answer with two significant figures) Fret ma mas = HN W= mg TemgtatesBymEor undo redo Teset keyboard shortcuts help N. Submit Reguest Anewer Part B Two reasons we know that the force of static friction does not increase when you push harder than the force calculated in PARTA. are (choose the best answer) O once t, reaches ma it cannot increase any further and the board would accelerate upwards if you could push hard enough to make t, exceed the weight of the board (We know this does not happen.) O the value of u, between the board and the wall increases as you push harder, but it cannot exceed 1 and the board would accelerate upwards if you could push hard enough to make , exceed the weight of the board (We know this does not happen.) OH you push too hard the wall will break and the value of u, between the board and the wall increases as you push harder, but it cannot exceed 1. O if you push too hard the wall will break and once , reaches mas t cannot increase any further. O if you push too hard the wall will break and the board would accelerate upwards if you could push hard enough to make f, exceed the weight of the board (We know this does not happen) O once t, reaches fmaxit cannot increase any further and the value of u, between the board and the wall increases as you push harder, but it cannot exceed 1.

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Chapter1: Units, Trigonometry. And Vectors
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## Part A

You want to nail a 1.9 kg board to the wall of a barn, as shown below. To position the board before nailing, you push it against the wall with a horizontal force \( F \) to keep it from sliding to the ground. The coefficient of static friction between the board and the wall is 0.64.

The least force you can apply and still hold the board in place is (enter your answer with two significant figures)

\[ F_{\text{net}} = ma \]

\[ f_{\text{max}} = \mu_s N \]

\[ W = mg \]

**Input Field for Calculation:**

A space to calculate and input the necessary force (\( N \)) to hold the board in place.

**Diagram Explanation:**

The diagram shows a person nailing a board to the wall, applying a horizontal force \( F \) to counteract the gravitational force pulling the board down. It illustrates the interaction between the normal force \( N \), frictional force \( f \), and gravitational force \( mg \).

## Part B

Two reasons we know that the force of static friction does not increase when you push harder than the force calculated in PART A are (choose the best answer):

- **(A)** Once \( f_s \) reaches \( f_{\text{max}} \), it cannot increase any further and the board would accelerate upwards if you could push hard enough to make \( f_s \) exceed the weight of the board (We know this does not happen).
  
- **(B)** The value of \( \mu_s \) between the board and the wall increases as you push harder, but it cannot exceed 1, and the board would accelerate upwards if you could push hard enough to make \( f_s \) exceed the weight of the board (We know this does not happen).

- **(C)** If you push too hard the wall will break and the value of \( \mu_s \) between the board and the wall increases as you push harder, but it cannot exceed 1.

- **(D)** If you push too hard the wall will break and once \( f_s \) reaches \( f_{\text{max}} \), it cannot increase any further.

- **(E)** Once \( f_s \) reaches \( f_{\text{max}} \), it cannot increase any further and the value of \( \mu_s \) between the board and
Transcribed Image Text:## Part A You want to nail a 1.9 kg board to the wall of a barn, as shown below. To position the board before nailing, you push it against the wall with a horizontal force \( F \) to keep it from sliding to the ground. The coefficient of static friction between the board and the wall is 0.64. The least force you can apply and still hold the board in place is (enter your answer with two significant figures) \[ F_{\text{net}} = ma \] \[ f_{\text{max}} = \mu_s N \] \[ W = mg \] **Input Field for Calculation:** A space to calculate and input the necessary force (\( N \)) to hold the board in place. **Diagram Explanation:** The diagram shows a person nailing a board to the wall, applying a horizontal force \( F \) to counteract the gravitational force pulling the board down. It illustrates the interaction between the normal force \( N \), frictional force \( f \), and gravitational force \( mg \). ## Part B Two reasons we know that the force of static friction does not increase when you push harder than the force calculated in PART A are (choose the best answer): - **(A)** Once \( f_s \) reaches \( f_{\text{max}} \), it cannot increase any further and the board would accelerate upwards if you could push hard enough to make \( f_s \) exceed the weight of the board (We know this does not happen). - **(B)** The value of \( \mu_s \) between the board and the wall increases as you push harder, but it cannot exceed 1, and the board would accelerate upwards if you could push hard enough to make \( f_s \) exceed the weight of the board (We know this does not happen). - **(C)** If you push too hard the wall will break and the value of \( \mu_s \) between the board and the wall increases as you push harder, but it cannot exceed 1. - **(D)** If you push too hard the wall will break and once \( f_s \) reaches \( f_{\text{max}} \), it cannot increase any further. - **(E)** Once \( f_s \) reaches \( f_{\text{max}} \), it cannot increase any further and the value of \( \mu_s \) between the board and
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