raiL A Determine the normal force exerted by the road on the car. A 1000-kg sports car (including the driver) crosses the rounded top of a hill (radius = 88.0 m ) at 17.0 m/s . Express your answer to three significant figures and include the appropriate units. FNcar = 6520 N Submit Previous Answers v Correct Part B Determine the normal force exerted by the car on the 73.0-kg driver. Express your answer to three significant figures and include the appropriate units. FNdriver = 476 N Submit Previous Answers v Correct Part C Determine the car speed at which the normal force on the driver equals zero. Express your answer to three significant figures and include the appropriate units. HÀ ? Value Units

raiL A Determine the normal force exerted by the road on the car. A 1000-kg sports car (including the driver) crosses the rounded top of a hill (radius = 88.0 m ) at 17.0 m/s . Express your answer to three significant figures and include the appropriate units. FNcar = 6520 N Submit Previous Answers v Correct Part B Determine the normal force exerted by the car on the 73.0-kg driver. Express your answer to three significant figures and include the appropriate units. FNdriver = 476 N Submit Previous Answers v Correct Part C Determine the car speed at which the normal force on the driver equals zero. Express your answer to three significant figures and include the appropriate units. HÀ ? Value Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

团 2 assingment 1. 1. What is the direction of the friction force on the block B? 2. Draw clear diagrams to show the forces on each of A, B and C. 3. By considering the equilibrium of A and C, calculate the tensions in the strings when there is no slipping. 4. Calculate the magnitude of the friction when there is no slipping. Now suppose that there insufficient friction to stop the block from slipping. 5. Write down the resultant force acting on each of A. B and C. 2 Ten boxes each of mass 5kg are stacked on top of cach other on the floor. G What forces act on the top box? What forces act on the bottom box? 3 The diagrams show a box of mass munder different systems of forces. 10 N F, N a In the first case the box is at rest. State the value of F- an In the second case the box is slipping. Write down the resultant horizontal force acting on it. II > ol
One of the great difficulties in landing on Venus is dealing with the crushing pressure of the atmosphere, which is 92 times the earth's atmospheric pressure. Part A If you are designing a lander for Venus in the shape of a hemisphere 2.3 m in diameter, how many newtons of inward force must it be prepared to withstand due to the Venusian atmosphere? (Don't forget about the bottom!) Express your answer with the appropriate units. HA F = Value Units Submit Request Answer Part B How much force would the lander have to withstand on the earth? Express your answer with the appropriate units. HA F = Value Units Submit Request Answer
Could you please help with part b? i am unsure as to how to get the average force
= 172.54(sin sin 40° ) +186.92(cos cos 45° )T, = 243.08 N SAMPLE PROBLEM 2 (equilibrium involving an inclined plane) A block resting on a plane inclined at an angle, e, of 42° from the horizontal is being held in place by a steel cable. The tension on the cable wire is 67.0 N. Figure 8. Block on an inclined plane held in place by a steel cable. a. Determine the normal force Nand the force due to gravity F- b. What is the mass of the block in kilograms?
Pls help with the following and explain the right answer, thank you. part B. Find the direction of this force as the angle measured counterclockwise from the +x+�-axis directed horizontally to the right. Express your answer in degrees.
Figure B 0.500 m Part C Block A has a mass of mд = 42.0 kg and rests on a flat surface. (Figure 3)The coefficient of static friction between the block and the surface is μA = 0.210. The coefficient of static friction between the rope and the fixed peg B is 0.340. The width of the block is d=0.200 m. Find the greatest mass, mc, that weight C can have such that block A does not move. Express your answer numerically in kilograms to three significant figures. ▸ View Available Hint(s) ΜΕ ΑΣΦ ↓↑ vec mc 30.6 T 0.200 m A 0.300 m Submit Previous Answers 0.400 m- × Incorrect; Try Again; 19 attempts remaining ? kg
3. A particle is acted upon by the following four forces: 21 N pulling east, 32 N pulling west, 52 N pulling north, and 42 N pulling south. a. Draw a diagram showing these four forces. b. Calculate the resultant and equilibrant of these forces. Content C3 Distinguish between the geometric representations of a single linear equation or a system of two linear equations in two- space and three- space, and determine different geometric configurations of lines and planes in three-space; Level
Part G
H4.
Part A In the fall of 2002, a group of scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60.0 kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a chain reaction. Neptunium-237 has a density of 19.5 g/cm³. What would be the radius r of a sphere of neptunium-237 that has a critical mass? Express your answer in centimeters to three significant figures. ▸ View Available Hint(s) r = 跖 ΕΠΙ ΑΣΦ 0 ? cm
You've already resp.. Tylon Clark-Algebr. Copy of Tylon Clark.. M escribing ons Help Last edit was 3 minutes ago rial 12 BIUA 三三 1 3 5 |II 6 I 1. Students will show works for this problem to receive credits: A 25 kg wood box is sliding across a wood surface, experiencing a coefficient (u) of kinetic friction of 0.20. The box is experiencing an applied force of +63 Newtons. What is the force of friction acting on the box? (Ff=u x Fn), (Fn=-Fg), (Fg%3Dmass x-9.81). P = m x v p= momentum m=mass V= velocity Directly proportional vs Inversely Proportional: When two variables are on different sides of the equal sign ( the equation), -if they are both on top of the fraction or both on the bottom of the fraction- directly proportional (Fc and m)( Fc and Vt) -if one is on the top of the fraction, one is on the bottom - inversely proportional (Fc and r) When two variahles are on the same sides of the egual sign III
Part D, please