The single line diagram of a three phase power system is shown in Fig.(2). The motor draws 15MWat 0.85 power factor leading at 13.7 kV terminal voltage. The data of the system elements are given afollows:G: 30 MVA, 13.2kV, X-0.1p.u.M: 20 MVA, 14kV, X-0.08 p.u.Load 2:5+j2 MVATr: 20 MVA, 13.8/138KVX-0.1 p.u.T:: 20 MVA, 13.2/132KV.X-0.12 p.u.Line: (20+j100) (21. Draw an impedance diagram showing all impedances in per unit. Select a base power of 50MVA and a base of 15KV in the motor zoneFind the terminal voltage of the generator.ofT₁38张AYATransmission linewww.T₂lymiz#YALoad 2

The single line diagram of a three phase power system is shown in Fig (2). The motor draws 15MW at 0.85 power factor leading at 13.7 kV terminal voltage. The data of the system elements are given a follows: G: 30 MVA, 13.2kV, X-0.1p.u. M: 20 MVA, 14kV, X-0.08 p.u. Load 2:5+j2 SVA J Tr: 20 MVA, 13.8/138kV.X-0.1 p.u. T:: 20 MVA, 13.2/132KV.X-0.12 p.u. Line: (20+j100) (2 1. Draw an impedance diagram showing all impedances in per unit. Select a base power of 50 MVA and a base of 15KV in the motor zone Find the terminal voltage of the generator. www. Transmission line Fig. (2) www Amm $YA M Load 2

The single line diagram of a three phase power system is shown in Fig (2). The motor draws 15MW at 0.85 power factor leading at 13.7 kV terminal voltage. The data of the system elements are given a follows: G: 30 MVA, 13.2kV, X-0.1p.u. M: 20 MVA, 14kV, X-0.08 p.u. Load 2:5+j2 SVA J Tr: 20 MVA, 13.8/138kV.X-0.1 p.u. T:: 20 MVA, 13.2/132KV.X-0.12 p.u. Line: (20+j100) (2 1. Draw an impedance diagram showing all impedances in per unit. Select a base power of 50 MVA and a base of 15KV in the motor zone Find the terminal voltage of the generator. www. Transmission line Fig. (2) www Amm $YA M Load 2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Fault Analysis

In an electrical engineering system, a fault is an abnormal electric current flowing through the system, and fault analysis is the study of these faults. For instance, a short-circuit is a fault where the live wire touches the ground or neutral wire. If a circuit is interrupted by a failure of a current-carrying wire then an open circuit fault occurs. The open-circuit faults are also called series faults. One or more phases or ground may be involved in a three-phase fault or may occur only between two phases. Current flows into the earth in case of a ground fault or earth fault. For most situations, the prospective short circuit current of a fault that is predictable can be calculated. To limit the loss of service because of a failure, the protective devices can detect fault conditions and operate circuit breakers and also other devices. All phases equally can be affected in a poly-phase system which is known as symmetric electrical fault. The asymmetric fault becomes more complicated to analyze if only some phases are affected. By using methods such as symmetrical components, the power system analysis of these types of faults is often simplified. The main objective of power system protection is to design, detect, and interrupt power system faults.

Question

The single line diagram of a three phase power system is shown in Fig.(2). The motor draws 15MW
at 0.85 power factor leading at 13.7 kV terminal voltage. The data of the system elements are given a
follows:
G: 30 MVA, 13.2kV, X-0.1p.u.
M: 20 MVA, 14kV, X-0.08 p.u.
Load 2:5+j2 MVA
Tr: 20 MVA, 13.8/138KVX-0.1 p.u.
T:: 20 MVA, 13.2/132KV.X-0.12 p.u.
Line: (20+j100) (2
1. Draw an impedance diagram showing all impedances in per unit. Select a base power of 50
MVA and a base of 15KV in the motor zone
Find the terminal voltage of the generator.
of
T₁
38
张
AYA
Transmission line
www.
T₂
lymiz
#YA
Load 2

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