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The sight distance of a sag parabolic curve is 116.85 m. long with grade tangents of -1.98% and +2.58% respectively. (a) Compute the length of the parabolic curve in m. (b) Compute the maximum velocity of car that can maneuver on the curve to avoid possible collision of any approaching cars in kPh and (c) determine the perception-reaction time of the driver to avoid collision in seconds. Assume coefficient of friction between tires and pavement to be 0.35.

The sight distance of a sag parabolic curve is 116.85 m. long with grade tangents of -1.98% and +2.58% respectively. (a) Compute the length of the parabolic curve in m. (b) Compute the maximum velocity of car that can maneuver on the curve to avoid possible collision of any approaching cars in kPh and (c) determine the perception-reaction time of the driver to avoid collision in seconds. Assume coefficient of friction between tires and pavement to be 0.35.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The sight distance of a sag parabolic curve is 116.85 m. long with grade tangents of -1.98% and +2.58% respectively. (a) Compute the length of the parabolic curve in m. (b) Compute the maximum velocity of car that can maneuver on the curve to avoid possible collision of any approaching cars in kPh and (c) determine the perception-reaction time of the driver to avoid collision in seconds. Assume coefficient of friction between tires and pavement to be 0.35.
Transcribed Image Text:The sight distance of a sag parabolic curve is 116.85 m. long with grade tangents of -1.98% and +2.58% respectively. (a) Compute the length of the parabolic curve in m. (b) Compute the maximum velocity of car that can maneuver on the curve to avoid possible collision of any approaching cars in kPh and (c) determine the perception-reaction time of the driver to avoid collision in seconds. Assume coefficient of friction between tires and pavement to be 0.35.
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