The shear strength of a normally consolidated clay can be given by the equation (tau)f=(sigma prime)tan(21). The results of a consolidated-undrained test on the clay are Chamber confining pressure 5 225 kN/m2 Deviator stress at failure 5 112 kN/m2
The shear strength of a normally consolidated clay can be given by the equation (tau)f=(sigma prime)tan(21). The results of a consolidated-undrained test on the clay are Chamber confining pressure 5 225 kN/m2 Deviator stress at failure 5 112 kN/m2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The shear strength of a normally consolidated clay can be given by the
equation (tau)f=(sigma prime)tan(21). The results of a consolidated-undrained test on the
clay are
Chamber confining pressure 5 225 kN/m2
Deviator stress at failure 5 112 kN/m2
Determine:
a. The consolidated-undrained (total stress) friction angle
b. Pore water pressure developed in the specimen at failure
Transcribed Image Text:12.19 The shear strength of a normally consolidated clay can be given by the
equation 7, = o' tan 21°. The results of a consolidated-undrained test on the
clay are
Chamber confining pressure 225 kN/m?
Deviator stress at failure 112 kN/m²
Determine:
a. The consolidated-undrained (total stress) friction angle
b. Pore water pressure developed in the specimen at failure
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