The shape of the T-distribution curve is wider than the normal curve becauseO a. it has more sample sizeO b. the curve is represented by degrees of freedomO c. the mean is also located at the end of the curveO d. it has higher varianceT-distribution is used whenO a. the population standard variance is unknown and the sample size is less than 30O b. the sample standard deviation is given and the population size is less than 30O c. the population standard deviation is unknown and the sample size is greater than 30O d. the sample size is greater than 30 and the population variance is known

If population standard deviation is known and large sample size i.e, n > 30 then we use z-…

Answered: The shape of the T-distribution curve…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8 cm. Find the probability that an individual distance is greater than 210.00 cm. Find the probability that the mean for 20 randomly selected distances is greater than 198.50 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not
Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular H2 27 27 0.79037 lb 0.80399 lb 0.00449 lb 0.00756 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? O A. Ho: H1 = H2 OB. Ho: H1#H2 Hq: Hy
Suppose a professor uses a normal distribution to assign grades in her math class. • She assigns an A to students scoring more than 1.9 standard deviations above the mean. • She assigns an F to students scoring more than 2.2 standard deviations below the mean. She assigns a B to students who Score between 1 and 1.9 standard deviations above the mean. • She assigns a D to students who Score between 1.2 and 2.2 standard deviations below the mean. • All other students get a C. Use the Cumulative Z-Score Table to answer the following questions. The Z-Score Table can be found below by selecting "Read". Write your answer as a percent using 2 decimal places. What percent of the class receives each grade assuming the scores are normally distributed? Hint % will recieve an A % will recieve a B % will recieve a C % will recieve a D % will recieve an F
Use the data and table below to test the indicated claim about the means of two populations. Assume that the two samples are independent simple randor samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Make sure you identify all values. An Exercise Science instructor at IVC was interested in comparing the resting pulse rates of students who exercise regularly and the pulse rates of those who de not exercise regularly. Independent simple random samples of 16 students who do not exercise regularly and 12 students who exercise regularly were selected and the resting pulse rates (in beats per minute) were recorded. The summary statistics are presented in the table below. Is there compelling statistical evidence that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly? Use a significance value of 0.05. Two-Sample T-Test Sample…
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A company produces steel rods. The lengths of the steel rods are distributed with a mean of 102.3-cm and a standard deviation of 2-cm. For shipment, 7 steel rods are bundled together. Round all answers to four decimal places if necessary. Note: When writing the distributions, they should be of the form (mean, variance) a. What is the distribution of X? X ~ ( b. What is the distribution of X? X~ N( c. For a single randomly selected steel rod, find the probability that the length is between 102.5-cm and 103.5-cm. d. For a bundled of 7 rods, find the probability that the average length is between 102.5-cm and 103.5- cm. e. For part d), is the assumption of normal necessary? Yes No
What type of distribution is referred to test the equal assumption of variance? 1. T distribution 2. Chi-square distribution 3. F distribution 4. Standard normal distribution
An experiment was conducted to determine whether giving candy to dining parties resulted in greater tips. The mean tip percentages and standard deviations are given in the accompanying table along with the sample sizes. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b). ... Question content area top right Part 1 μ n x s No candy μ1 36 18.61 1.39 Two candies μ2 36 21.26 2.34 * find the t stat * find the p value * State the conclusion * Construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean.
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Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular H2 26 26 0.79911 Ib 0.81326 Ib S 0.00445 Ib 0.00759 Ib ..... a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? A. Ho: Hy =H2 H1: 41> H2 B. Ho: H1 = H2 H1: 41
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