The series excitation winding resistance of the DC series motor fed with a nominal voltage of 3500 V is 8 ohms and the armature resistance is 2 ohms. The current drawn by the motor at full load is 0.2 times the starting current and the motor rotates at 1000 rpm at full load. Find the internal torque of the motor (Ta(full load) (armature moment). The starting resistance required to classify the current drawn by the motor at the time of starting to 2 times the full load current. Calculate (Ryv). Ta(full load) = PaOverload)= ryv=
The series excitation winding resistance of the DC series motor fed with a nominal voltage of 3500 V is 8 ohms and the armature resistance is 2 ohms. The current drawn by the motor at full load is 0.2 times the starting current and the motor rotates at 1000 rpm at full load. Find the internal torque of the motor (Ta(full load) (armature moment). The starting resistance required to classify the current drawn by the motor at the time of starting to 2 times the full load current. Calculate (Ryv). Ta(full load) = PaOverload)= ryv=
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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The series excitation winding resistance of the DC series motor fed with a nominal voltage of 3500 V is 8 ohms and the armature resistance is 2 ohms. The current drawn by the motor at full load is 0.2 times the starting current and the motor rotates at 1000 rpm at full load. Find the internal torque of the motor (Ta(full load) (armature moment). The starting resistance required to classify the current drawn by the motor at the time of starting to 2 times the full load current.
Calculate (Ryv).
Ta(full load) =
PaOverload)=
ryv=
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