240 V DC shunt motor draws 64 A line current at start-up. The shunt excitation winding resistance of the motor is 15 times the armature resistance. The motor draws 10 A line current from the source at full load. While the motor is unloaded, it rotates at 1500 rpm and draws 6A line current. Find the net output power of the motor at full load (Po(full load)), its efficiency at full load (u(full load)), the number of revolutions at full load (n(full load)) and its angular speed at full load (W(full load)). Po(full load)= u(full load)= n(full load) = w(full load)=
240 V DC shunt motor draws 64 A line current at start-up. The shunt excitation winding resistance of the motor is 15 times the armature resistance. The motor draws 10 A line current from the source at full load. While the motor is unloaded, it rotates at 1500 rpm and draws 6A line current. Find the net output power of the motor at full load (Po(full load)), its efficiency at full load (u(full load)), the number of revolutions at full load (n(full load)) and its angular speed at full load (W(full load)). Po(full load)= u(full load)= n(full load) = w(full load)=
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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240 V DC shunt motor draws 64 A line current at start-up. The shunt excitation winding resistance of the motor is 15 times the armature resistance. The motor draws 10 A line current from the source at full load. While the motor is unloaded, it rotates at 1500 rpm and draws 6A line current. Find the net output power of the motor at full load (Po(full load)), its efficiency at full load (u(full load)), the number of revolutions at full load (n(full load)) and its angular speed at full load (W(full load)).
Po(full load)=
u(full load)=
n(full load) =
w(full load)=
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