The sequence 11010 is used to modulate a band-pass carrier, f. 1.5kHz.a) Sketch the waveform for the three cases of binary ASK, FSK and PSKmodulation schemes, where f₁ =1kHz and f₂ =2kHz.b) Write down so(t) and s,(t) that represent the symbols 0 and 1, respectively.for all the three modulation schemes ASK, FSK and PSK.

Answered: The sequence 11010 is used to modulate…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Q2: Assume a sinusoidal signal with a frequency of 3.5 kHz and maximum amplitude of 1v. Then this signal is applied to LDM with a bit rate of 25kbps. Find the appropriate value of step size for this modulation.
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:A modulating signal is used to modulate a carrier signal(AM modulation). Let Pr , Pc, PSB, PUSB, PLSB and u are the total power, side band power, upper side band power, lower side band power and modulation index respectively. power, carrier Prove the following: a. Pc = Pr (me) m2 b. PSB = Pr m2 PLSB = 72+m2, c. PUSB = Pr 2+m2
D. Modi 39 In linear madulation. the intelligent signal in conveyed in A. The amplitude of the transmitled signal BA The sideband compenents of the transmitted wave C. The phase deviation modulated signal D. None of the above 40 What communication technique or modulation scheme make use of channel noise a an added advantage? A. Asynchnous shift key modulation B Vestigial sidehand modulation C Spread spectrum DA Widehand Frequency modulation Narowbund FM and AM share a lot ef similarities encept that AThe lower side frequencies ae 80 out of phase B. The upper side frequencies are 180 out of phase C. The sidehand fequencies are IH0 out of phase. D None of the sbove 41
modulating signal amplitude wideband FM dependent %m carrier swing Prompts Submitted Answers It determines the rate of frequency shift Choose a match frequency deviation The peak to peak frequency deviation Choose a match narrowband FM FM with modulation index between 1 and 10 Choose a match modulation index The ratio of actual frequency deviation to the maximum Choose a match modulating frequency allowable frequency deviation expressed in percentage. midband FM Frequency deviation of the carrier is to the Choose a match amplitude of the modulating signal. proportional inverse proportional
The baseband signal modulates a 98 kHz carrier sine wave. Using frequency and amplitude labelling similar to that in Figure 2, sketch the spectrum of the modulated signal using a template, similar to that in Figure 3, for the following modulations: AM with the amplitude of the carrier wave being 20 V DSBSC SSB – the lower sideband SSB – the upper sideband
23
Problem1: the figure shows multiple modulation schemes for the signal that is given by the dashed line sinusoidal function, the X-axis is the time axis is seconds and the Y-axis is the amplitude. Answer the following: 1. What is the value of the duty cycle in A? 2.What is the quantization noise in a modulator that uses a 4-bits register for the analog to digital conversion of the given sinusoidal signal?
In AM modulation, if the modulating signal amplitude is of 3.1V and carrier amplitude is of 10.93V, then the percentage of modulation is % m=
Q2: An audio signal given by 15 sin(4000nt) + 20 sin(8000nt) amplitude modulated(DSB-FC) a sinusoidal carrier wave 60 sin(100,000nt) a. Derive an expression for the modulated signal. b. Find the modulation index. c. Find the spectrum of the modulated signal. d. Sketch the spectrum of the modulated signal e. Which type of demodulation method you propose to reconstruct the audio at receiver. Why?
Q2: A modulating signal is used to modulate a carrier signal(AM modulation). Let Pr, Pc, PsB, PUSB, PLSB and u are the total power, carrier power, side band power, upper side band power, lower side band power and modulation index respectively. Prove the following: a. Pc = Pr (m2) m2 b. PsB = Pr m2 PT c. PUSB = PLSB 2+m2 2+m2

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