The s-domain circuit below has a number of impedance configurations seen between the various ports 1-6 which can be solved for with the switch open or closed. Please calculate the following impedances in a form that has a common denominator (simple, unfactored form is fine): a) With the switch open, solve the impedance seen between ports 1 and 2, that is Zız(s). b) With the switch open, solve the impedance seen between ports 3 and 4, that is Zu4(s). With the switch open, solve the impedance seen between ports 5 and 6, that is Zso(s). with the switch closed, solve the impedance seen between ports 1 and 2, that is new Ziz(s). With the switch closed, solve the impedance seen between ports 3 and 4, that is new Zu(s). With the switch closed, solve the impedance seen between ports 5 and 6, that is new Zx(s). e) d) e)
The s-domain circuit below has a number of impedance configurations seen between the various ports 1-6 which can be solved for with the switch open or closed. Please calculate the following impedances in a form that has a common denominator (simple, unfactored form is fine): a) With the switch open, solve the impedance seen between ports 1 and 2, that is Zız(s). b) With the switch open, solve the impedance seen between ports 3 and 4, that is Zu4(s). With the switch open, solve the impedance seen between ports 5 and 6, that is Zso(s). with the switch closed, solve the impedance seen between ports 1 and 2, that is new Ziz(s). With the switch closed, solve the impedance seen between ports 3 and 4, that is new Zu(s). With the switch closed, solve the impedance seen between ports 5 and 6, that is new Zx(s). e) d) e)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:The s-domain circuit below has a number of impedance configurations seen between the various ports 1-6
which can be solved for with the switch open or closed. Please calculate the following impedances in a
form that has a common denominator (simple, unfactored form is fine):
b)
a) With the switch open, solve the impedance seen between ports 1 and 2, that is Ziz(s).
With the switch open, solve the impedance seen between ports 3 and 4, that is Za(s).
With the switch open, solve the impedance seen between ports 5 and 6, that is Zs(s).
with the switch closed, solve the impedance seen between ports 1 and 2, that is new Ziz(s).
With the switch closed, solve the impedance seen between ports 3 and 4, that is new Zu(s).
f) with the switch closed, solve the impedance seen between ports 5 and 6, that is new Zx(s).
e)
d)
e)
3
1
6
Z₁2
000
L
R
W
2
fif
Z56
5
03
<- Z34
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