The rotor consists of 4 cylindrical segments which are fused together. The moment of inertia of a solid cylinder is I = (1/2)MR^2. To calculate I for the rotor, add the individual I values of the 4 cylindrical segments. This means that you will have to calculate the mass of each segment. Assume that the density of the rotor (M/V) is uniform. Recall that the volume of a cylinder is given by V = πR^2L.

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Chapter1: Units, Trigonometry. And Vectors
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going to calculate the theoretical value of the moment of inertia of the rotor, using the measurements given below. The rotor consists of 4 cylindrical segments which are fused together. The moment of inertia of a solid cylinder is I = (1/2)MR^2. To calculate I for the rotor, add the individual I values of the 4 cylindrical segments. This means that you will have to calculate the mass of each segment. Assume that the density of the rotor (M/V) is uniform. Recall that the volume of a cylinder is given by V = πR^2L.

face-on view of rotor
edge-on view of rotor
R2 = 10.11 cm
L1 = 5.29 cm
1
R3 =
5.10 cm
L2 = 1.50 cm
2
L3 = 0.900 cm 1
3
R1 = R4 = 1.50 cm
L4 = 4.14 cm
total mass of rotor:
M = 5.228 kg
Transcribed Image Text:face-on view of rotor edge-on view of rotor R2 = 10.11 cm L1 = 5.29 cm 1 R3 = 5.10 cm L2 = 1.50 cm 2 L3 = 0.900 cm 1 3 R1 = R4 = 1.50 cm L4 = 4.14 cm total mass of rotor: M = 5.228 kg
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