A uniform rod of length 1.44 m is attached to a frictionless pivot at one end. It is released from rest from an angle θ = 22.9 ° above the horizontal.   What is the equation for the initial torque of the rod?  L/2*m*g*sin(90° - θθ)  L/2*m*g*sin(θθ)  -L*m*g*sin(θθ)  -L/2*m*g*sin(90° - θθ)  L*m*g*sin(90° - θθ)  -L/2*m*g*sin(θθ)  -L*m*g*sin(90° - θθ)  L*m*g*sin(θθ) What is the correct expression for the moment of inertial of the rod about the pivot at its edge?  1/12*m*(L/2)^2  1/3*m*(L/2)^2  1/3*m*L^2  1/12*m*L^2 Find the magnitude of the initial angular acceleration of the rod. Find the magnitude of the initial linear acceleration of a point at the center of the rod.

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Chapter1: Units, Trigonometry. And Vectors
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A uniform rod of length 1.44 m is attached to a frictionless pivot at one end. It is released from rest from an angle θ = 22.9 ° above the horizontal.

 

What is the equation for the initial torque of the rod?


 L/2*m*g*sin(90° - θθ)
 L/2*m*g*sin(θθ)
 -L*m*g*sin(θθ)
 -L/2*m*g*sin(90° - θθ)
 L*m*g*sin(90° - θθ)
 -L/2*m*g*sin(θθ)
 -L*m*g*sin(90° - θθ)
 L*m*g*sin(θθ)

What is the correct expression for the moment of inertial of the rod about the pivot at its edge?


 1/12*m*(L/2)^2
 1/3*m*(L/2)^2
 1/3*m*L^2
 1/12*m*L^2

Find the magnitude of the initial angular acceleration of the rod.

Find the magnitude of the initial linear acceleration of a point at the center of the rod.

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