The rigid horizontal bar ABC of negligible mass is connected to two rods as shown in the figure. If the system is initially stress-free, a temperature change will cause a tensile stress of 125 MPa in the brass rod. Assume that both rods are subjected to the same change in temperature. a. Calculate the stress in the copper bar (in MPa). b. Calculate the axial deformation in the brass bar (in mm). c. Calculate the axial deformation in the brass bar (in mm). d. Calculate the change in temperature. Indicate increase or decrease in temperature.
The rigid horizontal bar ABC of negligible mass is connected to two rods as shown in the figure. If the system is initially stress-free, a temperature change will cause a tensile stress of 125 MPa in the brass rod. Assume that both rods are subjected to the same change in temperature. a. Calculate the stress in the copper bar (in MPa). b. Calculate the axial deformation in the brass bar (in mm). c. Calculate the axial deformation in the brass bar (in mm). d. Calculate the change in temperature. Indicate increase or decrease in temperature.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The rigid horizontal bar ABC of negligible mass is connected to two rods as shown in the figure. If the system is initially stress-free, a temperature change will cause a tensile stress of 125 MPa in the brass rod. Assume that both rods are subjected to the same change in temperature.
a. Calculate the stress in the copper bar (in MPa).
b. Calculate the axial deformation in the brass bar (in mm).
c. Calculate the axial deformation in the brass bar (in mm).
d. Calculate the change in temperature. Indicate increase or decrease in temperature.
Transcribed Image Text:9. The rigid horizontal bar ABC of negligible mass is connected to two rods as
shown in the figure. If the system is initially stress-free, a temperature change will
cause a tensile stress of 125 MPa in the brass rod. Assume that both rods are
subjected to the same change in temperature.
Brass
L = 2 m
A = 1200 mm²
E = 100 GPa
Ca = 18.7 × 10-6/°C
A
В
- 3 m
- 2 m
Copper
L= 3 m
A = 1500 mm²
E = 120 GPa
a = 16.8 × 10-6/°C
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