The researcher at AUA has a hypothesis that on average it takes more than 6 weeks for the AUA bachelor student to find a job after the graduation. To test this assumption a random sample of 50 AUA bachelor graduates are taken with mean of 6.3 and standard deviation of 1.2. Test the hypothesis with the significance level of alpha = 0.05. The test statistics is equal to and the critical value is equal to thus The Null hypothesis that ]is[ not rejected mu is more than or equal to 6 -2.01 mu is less than or equal to 6 -1.77 mu is more than 6 rejected 2.01 1.77 1.68

The researcher at AUA has a hypothesis that on average it takes more than 6 weeks for the AUA bachelor student to find a job after the graduation. To test this assumption a random sample of 50 AUA bachelor graduates are taken with mean of 6.3 and standard deviation of 1.2. Test the hypothesis with the significance level of alpha = 0.05. The test statistics is equal to and the critical value is equal to thus The Null hypothesis that ]is[ not rejected mu is more than or equal to 6 -2.01 mu is less than or equal to 6 -1.77 mu is more than 6 rejected 2.01 1.77 1.68

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The average American consumes 100 liters of alcohol per year. Does the average college student consume more alcohol per year? A researcher surveyed 13 randomly selected college students and found that they averaged 107.9 liters of alcohol consumed per year with a standard deviation of 19 liters. Assuming that the data come from a normally distributed population, what can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: The test statistic= The p-value =
An avionics company uses a new production method to manufacture aircraft altimeters. A single random sample of new altimeters resulted in the errors listed below. Use a 5% significance level to test the claim that the new production method has errors with a standard deviation greater than 32.2 ft, which was the standard deviation for the old production model (o). If it appears that the standard deviation is greater, does the new production method appear to be better or worse than the old method? Should the company take any action? -42 78 -22 -72 -45 15 17 51 -5 -53 -9 -109 Find the upper and lower boundaries of the 95% confidence interval for o. 98 37 32 73 89
A sample of 12 concrete specimens from supplier A were tested for their compressive strength. The results gave an average of 85 MPa and a standard deviation of 4 MPa. From supplier B, 10 specimens were similarly tested and gave an average compressive strength of 81 MPa and a standard deviation of 5 MPa. (a) Using procedures of Hypothesis Testing, can we conclude at the 0.05 level of significance that the compressive strength of concrete from A exceeds that from B by more than 2 MPa? Assume the populations to be approximately normal with equal variances. (b) Is the assumption of equal variances in (a) justifiable at an a = 0.10?
Suppose the average size of a new house built in a certain county in 2014 was 2,270 square feet. A random sample of 25 new homes built in this county was selected in 2018. The average square footage was 2,191, with a sample standard deviation of 223 square feet. Complete parts a and b. Using α=0.02, does this sample provide enough evidence to conclude that the average house size of a new home in the county has changed since 2014? Determine the null and alternative hypotheses.
2. A pain reliever currently being used in a hospital is known to bring relief in a mean time of 3.5 minutes. To compare a new pain reliever with the one currently being used, a random sample of 45 patients is given the new drug. The mean time to relief for this sample is 2.8 minutes with a standard deviation of 1.14 minutes. a) Test the research (alternative) hypothesis that the new drug is more effective than the old drug, using α ≤ .05. b) Assuming a standard deviation of 1.14 minutes, approximately how large a sample of patients would be needed to form a 90% confidence interval to estimate the population time-to-relief of the new drug accurate to within plus or minus 10 seconds? Answers: 2. a) Z = -4.12, reject H0, new drug is more effective, b) 127
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a α=0.05 level of significance. Give answer to at least 4 decimal places. Hours 48 41 60 55 48 68 53 55 50 49 54 52 What are the correct hypotheses? H0: hours Ha: hours
A random sample of 23 bags of apples (marked as 10 pounds each) received by a large grocery chain tested out as having a mean of 9.2 pounds with a variance of 2.56 pounds. Test whether the true mean of all bags is under 10 pounds. Set up hypotheses. Perform the appropriate test by showing your formula. Interpret the results using a Type I (alpha) error of .05. Also provide the p value here. Also construct a 95% confidence interval around your sample mean (X bar) that should contain the true mean (mu). Also interpret this interval.
In a sample of n= 19 lichen specimens, the researchers found the mean and standard deviation of the amount of the radioactive element, cesium-137, that was present to be 0.009 and 0.005 microcurie per milliliter, respectively. Suppose the researchers want to increase the sample size in order to estimate the mean u to within 0.002 microcurie per milliliter of its true value, using a 95% confidence interval. Complete parts a through c. a. What is the confidence level desired by the researchers? The confidence level is.
A survey using a sample size of 11 reveals that the average size of dairy farms in Simcoe County is 1500 hectares with a standard deviation of 150 hectares. As a researcher, you take this information and conduct a hypothesis test and find the calculated value of the test statistic is 2.2. Prior to the study, the following hypotheses were established: но: и - 1400 H1: u > 1400 Use a = 0.01. Based on the test statistic and sample size, what the p-value is so we should the null hypothesis. _(0.0262, .0262, 0.026, .026) Given that the p-value is (greater/less) (greater, larger, >, bigger) than a, we should (accept/reject) _ lаccept) the null hypothesis. 0.062, reject ) 0.0131, accept 0.0026, reject ) 0.0262, accept 0.062, accept
A health professional obtains records for 33 patients who have undergone a certain surgical procedure and finds the average length of stay is 3.23 days with a standard deviation of 1.58 days. Using α=0.10 is there evidence to suggest the actual average length of stay for this surgical procedure is 3 days? The correct conclusion is that we Select an answer: (can, maybe can, cannot) conclude that the average length of stay of Select an answer: (all, sampled, randomly selected) surgeries of this type Select an answer: (is less than, is is different from, is more than) Select an answer: (3.23, 0.85, 3) days.What level of concern do you have for the validity of your results? Moderate - the original data is not normally distributed which is an assumptions violation Low - our sample size is near 30, so while that's likely sufficient for X¯ to be approximately normally distributed, seeing that the original data isn't extremely skewed would make us feel more comfortable Extreme - we…
Guidelines for the Jolly Blue Giant Health Insurance Company claim that the average hospitalization for a triple hernia operation should not exceed 30 hours. A diligent auditor studied records of 16 randomly chosen triple hernia operations at Hackmore Hospital and found a mean hospital stay of 20 hours with a standard deviation of 20 hours. Conduct a hypothesis test to see if the auditor can prove that the average does not exceed 30. (α=.025) Assume that the hospitalization time is normally distributed.