Answered: The regular expression (ab* + c)"b will…

The regular expression (ab* + c)"b will produce which of the following sets? O({a} {b} {c})* {b} O({a} {b}* U {c})* {b} . (({a} {b}) {c})* {b} ({a} {b} {c})* {b}

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++ without using std:: Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >>…
2. Replace the even locations in the vector m= [7 9 2 4 5 8 10 3] with the following set of elements [1036 7] Your answer
1- Let A = [2: 0.5: 4],and B=B(2:4). What are the value of a ,and B?
Let A = {47, 49, 51, 53}, which of these is a correct set builder notation for A? There may be more than one correct answer. A. {2x +1 : r e Z and 23 < a < 26} O B. {x : a is odd and 47 < a < 53} C. {r : x is odd and 47 < a< 53} D. {r : a is odd and 46 < a < 54} E. {2x +1:r € Z and 23
x <- bubblesort(sample(1:6, size=5, replace=T)) if (x[1]==x[5]){ hand <-"Yahtzee" } else if (x[1]==x[4] ] x[2]==x[5]) { hand <- "4ofKind" } } else { hand <-"Chance" } The above code lays this out for Yahtzee and 4 of a kind. Find statements that work for the rest and put this into a function called get hand , which returns what type of hand was rolled from a sorted roll of five dice. Make sets of rolls and test them to make sure they work. Note that above we use an else if, which allows us to test multiple conditions in an if-else statement.
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int a[100], b[1000], c[1000]; // get some data for a, b, and c for (i = 0; i < 100; i++) for (j = 0; j < 10; j++) a[i] += c[j*100 + i] * b[j*100 + i] ;
Data Structures and Algorithms in C/C++ a) Implement the addLargeNumbers function with the following prototype: void addLargeNumbers(const char *pNum1, const char *pNum2); This function should output the result of adding the two numbers passed in as strings. Here is an example call to this function with the expected output: /* Sample call to addLargeNumbers */ addLargeNumbers("592", "3784"); /* Expected output */ 4376 b) Implement a test program that demonstrates adding at least three pairs of large numbers (numbers larger than can be represented by a long). c) (1 point) Make sure your source code is well-commented, consistently formatted, uses no magic numbers/values, follows programming best-practices, and is ANSI-compliant.
Consider the set A = {1, 2, 11, {121}, 22, 1212, (111, 212, 112}} Enter the value of Al. (Note: Enter a number).
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Write a C function arrDivN() that takes one array of integers and three integer numbers (say ar, n1, n2, n3) as parameters, it stores into the array the numbers divisible by n3 between n1 and n2 (both inclusive) and returns the count of the numbers stored in the array. Prototype: int arrDivN(int ar[], int n1, int n2, int n3);