The Keg for the reaction of water with water is called KwH₂O + H₂O → H3O+1 + OH-¹[H3O+¹][OH-¹]Kw==[H₂O]²The inverse logarithm, or -log, of [H3O+¹][OH^¹] = 10-¹4 is pH + pOH = 141. What happens to the [H3O+¹] when base is added to neutral water?the [H3O+¹] goes[H3O+¹][OH-¹] = (1 x 10-7)² = 1 x 10-142. What happens to the pH when base is added to neutral water?an example of a decreased [H3O+1] is [H3O+¹] = 1 × 10-8. Thus pH = -log[108] = 8a. downthus, adding acid makes the pH go3. What happens to the [H3O+¹] when base is added to neutral water?in the equation [H3O+¹][OH¯¹] = 10-14, when [OH-¹] increases, the [H3O+¹] goes4. What happens to the pOH when base is added to neutral water?when [OH-¹] increases, the pOH goesthis can also be seen using pH + pOH = 145. What happens to the Kw when base is added to neutral water?because it's a constant.b. upc. no changesince the pOH = -log[OH-¹]

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The Reg for the H₂O + H₂O → Kw [H3O+¹][OH-¹] tion of water with Wal is called Zw H3O+1 + OH-1 [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH-¹] = 10-14 is pH + pOH = 14 1. What happens to the [H3O+¹] when base is added to neutral water? the [H3O+¹] goes [H3O+¹][OH-¹] (1 x 10-7)² = 1 x 10-14 2. What happens to the pH when base is added to neutral water? an example of a decreased [H3O+¹] is [H3O+¹] = 1 x 10-8. Thus pH = -log[108] = 8 thus, adding acid makes the pH go 3. What happens to the [H3O+1] when base is added to neutral water? in the equation [H3O+¹][OH-¹] = 10-14, when [OH-¹] increases, the [H3O+¹] goes 4. What happens to the pOH when base is added to neutral water? when [OH-¹] increases, the pOH goes a. down this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water? because it's a constant. b. up c. no change since the pOH = -log[OH-¹]

The Reg for the H₂O + H₂O → Kw [H3O+¹][OH-¹] tion of water with Wal is called Zw H3O+1 + OH-1 [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH-¹] = 10-14 is pH + pOH = 14 1. What happens to the [H3O+¹] when base is added to neutral water? the [H3O+¹] goes [H3O+¹][OH-¹] (1 x 10-7)² = 1 x 10-14 2. What happens to the pH when base is added to neutral water? an example of a decreased [H3O+¹] is [H3O+¹] = 1 x 10-8. Thus pH = -log[108] = 8 thus, adding acid makes the pH go 3. What happens to the [H3O+1] when base is added to neutral water? in the equation [H3O+¹][OH-¹] = 10-14, when [OH-¹] increases, the [H3O+¹] goes 4. What happens to the pOH when base is added to neutral water? when [OH-¹] increases, the pOH goes a. down this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water? because it's a constant. b. up c. no change since the pOH = -log[OH-¹]

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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