The recovery time from COVID19 is normally distributed with a mean of 12 days and a standard deviation of 2 days. 1)What is the probability that a randomly selected COVID19 patient recovers within a week? 2)What is the probability that a randomly selected COVID19 patient takes between 9 and 15 days to recover?
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The recovery time from COVID19 is
days.
1)What is the probability that a randomly selected COVID19 patient recovers within a week?
2)What is the probability that a randomly selected COVID19 patient takes between 9 and 15 days to recover?
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- For a certain knee surgery, a mean recovery time of 13 weeks is typical. With a new style of physical therapy, a researcher claims that the mean recovery time, μ, is less than 13 weeks. In a random sample of 32 knee surgery patients who practiced this new physical therapy, the mean recovery time is 12.8 weeks. Assume that the population standard deviation of recovery times is known to be 1.1 weeks. Is there enough evidence to support the claim that the mean recovery time of patients who practice the new style of physical therapy is less than 13 weeks? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis Ho and the alternative hypothesis H₁. H Ho: O H₁:0 OO 020 ローロ OO ? (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by x-μ √n • The p-value is the area under the curve to the left of the value of the test statistic. Standard Normal Distribution 04 Step 1:…The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 4.1 years and a standard deviation of 0.5 years. He then randomly selects records on 42 laptops sold in the past and finds that the mean replacement time is 3.9 years.Assuming that the laptop replacement times have a mean of 4.1 years and a standard deviation of 0.5 years, find the probability that 42 randomly selected laptops will have a mean replacement time of 3.9 years or less.P(M < 3.9 years)The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.6 years and a standard deviation of 0.4 years. He then randomly selects records on 48 laptops sold in the past and finds that the mean replacement time is 3.4 years. Assuming that the laptop replacement times have a mean of 3.6 years and a standard deviation of 0.4 years, find the probability that 48 randomly selected laptops will have a mean replacement time of 3.4 years or less. P(M < 3.4 years)=__________
- An article in Knee Surgery Sports Traumatology, Arthroscopy, "Effect of provider volume on resource utilization for surgical procedures," (2005, Vol. 13, pp. 273-279) showed a mean time of 116 minutes and a standard deviation of 18 minutes for ACL reconstruction surgery for high-volume hospitals (with more than 300 such surgeries per year). If a high-volume hospital needs to schedule 10 surgeries, what is the mean and variance of the total time to complete these surgeries? Assume the times of the surgeries are independent and normally distributed. Mean = i Variance = i minutes minutes²The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.3 years and a standard deviation of 0.4 years. He then randomly selects records on 25 laptops sold in the past and finds that the mean replacement time is 3.2 years.Assuming that the laptop replacement times have a mean of 3.3 years and a standard deviation of 0.4 years, find the probability that 25 randomly selected laptops will have a mean replacement time of 3.2 years or less.P(M < 3.2 years) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.Based on the result above, does it appear that the computer store has been given laptops of lower than average quality? No. The probability of obtaining this data is high enough…The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 4.1 years and a standard deviation of 0.6 years. He then randomly selects records on 41 laptops sold in the past and finds that the mean replacement time is 3.9 years.Assuming that the laptop replacement times have a mean of 4.1 years and a standard deviation of 0.6 years, find the probability that 41 randomly selected laptops will have a mean replacement time of 3.9 years or less.P(M < 3.9 years) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.Based on the result above, does it appear that the computer store has been given laptops of lower than average quality?
- Researchers interested in determining the relative effectiveness of two different drug treatments on people with a chronic illness established two independent test groups. The first group consisted of 12 people with the illness, and the second group consisted of 14 people with the illness. The first group received treatment 1 and had a mean time until remission of 166 days with a standard deviation of 8 days. The second group received treatment 2 and had a mean time until remission of 163 days with a standard deviation of 9 days. Assume that the populations of times until remission for each of the two treatments are normally distributed with equal variance. Construct a 90% confidence interval for the difference −μ1μ2 between the mean number of days before remission after treatment 1 ( μ1 ) and the mean number of days before remission after treatment 2 ( μ2 ). Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate…The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.8 years and a standard deviation of 0.5 years. He then randomly selects records on 36 laptops sold in the past and finds that the mean replacement time is 3.5 years.Assuming that the laptop replacment times have a mean of 3.8 years and a standard deviation of 0.5 years, find the probability that 36 randomly selected laptops will have a mean replacment time of 3.5 years or less.P(¯xx¯ < 3.5 years) = Enter your answer as a number accurate to 4 decimal places.Based on the result above, does it appear that the computer store has been given laptops of lower than average quality?The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 4.5 years and a standard deviation of 0.4 years. He then randomly selects records on 48 laptops sold in the past and finds that the mean replacement time is 4.4 years.Assuming that the laptop replacement times have a mean of 4.5 years and a standard deviation of 0.4 years, find the probability that 48 randomly selected laptops will have a mean replacement time of 4.4 years or less.P(M < 4.4 years) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
- The recovery time from COVID19 is normally distributed with a mean of 12 days and a standard deviation of 2 days. 20. What is the probability that a randomly selected COVID19 patient recovers within a week?A. 0.0049B. 0.0051C. 0.0062D. 0.0581 21. What is the probability that a randomly selected COVID19 patient takes between 9 and 15 days to recover?A. 0.8152B. 0.7831C. 0.9275D. 0.8664A random sample of 10 subjects have weights with a standard deviation of 10.9654 kg what is the variance of their weights be sure to include the appropriate units with the resultA randomized controlled trial is run to evaluate the effectiveness of a new drug for asthma in children. A total of 250 children are randomized to either the new drug or a placebo (125 per group). The mean age of children assigned to the new drug is 12.4 with a standard deviation of 3.6 years. The mean age of children assigned to the placebo is 13.0 with a standard deviation of 4.0 years. Suppose that there are 63 boys assigned to the new drug group and 58 boys assigned to the placebo group. Is there a statistically significant difference in the proportions of boys assigned to the treatments? Run the appropriate test at a 5% level of significance.