The reaction CO(g) + Cl2(g) ↔ COCl2(g) has Kc = 4.6×109. If initially all products and reactants are equal concentrations, then how would the concentrations of the reactants compare to the concentration of the products at equilibrium? Group of answer choices The reactants would be higher in concentration than products. The reactants would be lower in concentration than products. The reactants would have the exact same concentration as the products (the reaction is at equilibrium). There is not enough information given to determine how concentrations would compare.
The reaction CO(g) + Cl2(g) ↔ COCl2(g) has Kc = 4.6×109. If initially all products and reactants are equal concentrations, then how would the concentrations of the reactants compare to the concentration of the products at equilibrium? Group of answer choices The reactants would be higher in concentration than products. The reactants would be lower in concentration than products. The reactants would have the exact same concentration as the products (the reaction is at equilibrium). There is not enough information given to determine how concentrations would compare.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The reaction CO(g) + Cl2(g) ↔ COCl2(g) has Kc = 4.6×109. If initially all products and reactants are equal concentrations, then how would the concentrations of the reactants compare to the concentration of the products at equilibrium?
Group of answer choices
The reactants would be higher in concentration than products.
The reactants would be lower in concentration than products.
The reactants would have the exact same concentration as the products (the reaction is at equilibrium).
There is not enough information given to determine how concentrations would compare.
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