The reaction shown forms two major substitution products. Draw both products and write a mechanism where instructed. Clearly show stereochemistry by drawing a wedged bond, a hashed bond, and two in-plane bonds for each chiral carbon. Parts have been pre-drawn for your convenience-do not delete these. Step 1: Draw a curved arrow. Select Draw Rings More H с H Erase Br Q 2 Q CH3OH Step 2: Complete the intermediate and draw a curved arrow. Select Draw Rings More → H : Br C H Br O : 0: H Erase Q2Q
The reaction shown forms two major substitution products. Draw both products and write a mechanism where instructed. Clearly show stereochemistry by drawing a wedged bond, a hashed bond, and two in-plane bonds for each chiral carbon. Parts have been pre-drawn for your convenience-do not delete these. Step 1: Draw a curved arrow. Select Draw Rings More H с H Erase Br Q 2 Q CH3OH Step 2: Complete the intermediate and draw a curved arrow. Select Draw Rings More → H : Br C H Br O : 0: H Erase Q2Q
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The image depicts a user interface for drawing chemical structures, emphasizing the completion of final products with stereochemistry and lone pairs where applicable.
**Text Instruction:**
- **Step 3:** Complete the final products. Clearly show stereochemistry and lone pairs where applicable.
**Interface Overview:**
- **Toolbar Options:**
- **Select, Draw, Rings, More**: Options for manipulating the drawing.
- **Icons**: Tools for drawing bonds (single, double, etc.), adding atoms (C, H, O), and erasing.
**Chemical Structures:**
- **Displayed Molecules:**
- **Two hexagonal ring structures**, each with a hydrogen atom (H) attached.
- **Wedge and Dash Bonds:** Indicating 3D stereochemistry. The wedge suggests a bond coming out of the plane, and the dashed line implies a bond going behind the plane.
**Navigation Tools:**
- **Undo/Redo Buttons**: Allow user to revert or repeat actions.
- **Zoom Buttons**: Facilitate zooming in and out of the drawing area.
The purpose of this interface is to assist students or users in accurately visualizing and drawing chemical structures while considering stereochemistry.

Transcribed Image Text:**Mechanism of Substitution Reaction**
**Overview:**
The reaction illustrated forms two major substitution products. The task is to draw both products and illustrate the mechanism as instructed while clearly showing stereochemistry. Represent stereochemistry by using a wedged bond, a hashed bond, and two in-plane bonds for each chiral carbon. Parts have been pre-drawn for convenience—do not delete these.
**Step 1: Draw a Curved Arrow**
- The left panel shows a cyclohexane ring with a bromine (Br) attached, drawn with stereochemistry: one bond is a solid wedge, indicating a bond coming out of the plane, and another a dashed wedge, indicating a bond going into the plane.
- To the left of the diagram, there are tool options labeled "Select", "Draw", "Rings", "More", and "Erase". Drawing options include straight lines, curved arrows, and stereochemical indicators (solid wedges and dashed wedges). Elements like carbon (C), hydrogen (H), and bromine (Br) are selectable.
- A curved arrow is drawn, originating from the lone pair on bromine.
**Step 2: Complete the Intermediate and Draw a Curved Arrow**
- The right panel shows the cyclohexane ring without bromine, and methanol (CH₃OH) is added to the reaction.
- The methanol structure is shown with a lone pair on oxygen, which is involved in the substitution mechanism.
- Ensure that the stereochemistry is maintained as per the initial structure.
- Continue the mechanism by drawing a curved arrow from the lone pair on the oxygen towards the carbon on the ring where bromine was attached.
**Reaction Conditions:**
- The reagent CH₃OH is indicated, which acts as a nucleophile in the reaction mechanism.
**Conclusion:**
Follow these steps meticulously to ensure accurate depiction of the reaction mechanism and the stereochemistry of the resulting substitution products.
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