The reaction below precedes via an E2 elimination versus an SN2 reaction. Circle all of the answers that correctly support this reaction outcome. NaOCH3 + Naci CH;OH The nucleophilicity of the methoxide anion (CH3O) is reduced in protic solvent The primary alkyl halide provides too much sterics for an effective SN2 reaction to occur Sodium methoxide (NaOCH3) is a strong enough base to deprotonate the alkyl chloride Stable primary carbocations can form beta-hydrogens on the carbon adjacent to the chloro group are available for deprotonation O O 0 00

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The reaction below precedes via an E2 elimination versus an SN2 reaction. Circle all of the answers that correctly support this reaction outcome.
NaOCH3
+ Naci
CH;OH
The nucleophilicity of the methoxide anion (CH3O) is reduced in protic solvent
The primary alkyl halide provides too much sterics for an effective SN2 reaction to occur
Sodium methoxide (NaOCH3) is a strong enough base to deprotonate the alkyl chloride
Stable primary carbocations can form
beta-hydrogens on the carbon adjacent to the chloro group are available for deprotonation
O O O O O
Transcribed Image Text:The reaction below precedes via an E2 elimination versus an SN2 reaction. Circle all of the answers that correctly support this reaction outcome. NaOCH3 + Naci CH;OH The nucleophilicity of the methoxide anion (CH3O) is reduced in protic solvent The primary alkyl halide provides too much sterics for an effective SN2 reaction to occur Sodium methoxide (NaOCH3) is a strong enough base to deprotonate the alkyl chloride Stable primary carbocations can form beta-hydrogens on the carbon adjacent to the chloro group are available for deprotonation O O O O O
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