The reaction 5 Br (aq) + BrO3¯ (aq) + 6H+ (aq) + 3Br2 (1) + 3H20 (I) is expected to obey the mechanism BrO3 (aq) + H* (aq) HBrОз (аq) + Ht (aq) + H2BrO3" (aq) e HBRO3 (aq) - H2BRO3* (aq) (Br-BrO2) (aq) + H20 (1) Fast Fast Slow Br (aq) (Br-BrO2) (aq) + 4H+ (aq) + 4Br (aq) 3B12 (1) + 3H20 (I) Fast Write the rate law.

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### Chemical Kinetics: Determining the Rate Law for a Reaction

#### The Reaction

The overall reaction being studied is:

\[ 5 \text{Br}^- (\text{aq}) + \text{BrO}_3^- (\text{aq}) + 6\text{H}^+ (\text{aq}) \rightleftharpoons 3 \text{Br}_2 (\text{l}) + 3 \text{H}_2\text{O} (\text{l}) \]

This reaction is expected to follow a specific mechanism to reach its final products.

#### Proposed Reaction Mechanism

The mechanism consists of multiple steps:

1. **First Step (Fast Equilibrium)**
   \[ \text{BrO}_3^- (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{HBrO}_3 (\text{aq}) \]

2. **Second Step (Fast Equilibrium)**
   \[ \text{HBrO}_3 (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{H}_2\text{BrO}_3^+ (\text{aq}) \]

3. **Third Step (Slow)**
   \[ \text{Br}^- (\text{aq}) + \text{H}_2\text{BrO}_3^+ (\text{aq}) \rightarrow (\text{Br-BrO}_2) (\text{aq}) + \text{H}_2\text{O} (\text{l}) \]

4. **Fourth Step (Fast)**
   \[ (\text{Br-BrO}_2) (\text{aq}) + 4\text{H}^+ (\text{aq}) + 4\text{Br}^- (\text{aq}) \rightarrow 3\text{Br}_2 (\text{l}) + 3\text{H}_2\text{O} (\text{l}) \]

These steps illustrate the detailed progress of the reaction through intermediate states before forming the final products.

#### Task: Writing the Rate Law

Your task is to write the rate law for this reaction based on the proposed mechanism. To determine the rate law, focus on the slowest step in the mechanism, which is often the rate
Transcribed Image Text:### Chemical Kinetics: Determining the Rate Law for a Reaction #### The Reaction The overall reaction being studied is: \[ 5 \text{Br}^- (\text{aq}) + \text{BrO}_3^- (\text{aq}) + 6\text{H}^+ (\text{aq}) \rightleftharpoons 3 \text{Br}_2 (\text{l}) + 3 \text{H}_2\text{O} (\text{l}) \] This reaction is expected to follow a specific mechanism to reach its final products. #### Proposed Reaction Mechanism The mechanism consists of multiple steps: 1. **First Step (Fast Equilibrium)** \[ \text{BrO}_3^- (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{HBrO}_3 (\text{aq}) \] 2. **Second Step (Fast Equilibrium)** \[ \text{HBrO}_3 (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{H}_2\text{BrO}_3^+ (\text{aq}) \] 3. **Third Step (Slow)** \[ \text{Br}^- (\text{aq}) + \text{H}_2\text{BrO}_3^+ (\text{aq}) \rightarrow (\text{Br-BrO}_2) (\text{aq}) + \text{H}_2\text{O} (\text{l}) \] 4. **Fourth Step (Fast)** \[ (\text{Br-BrO}_2) (\text{aq}) + 4\text{H}^+ (\text{aq}) + 4\text{Br}^- (\text{aq}) \rightarrow 3\text{Br}_2 (\text{l}) + 3\text{H}_2\text{O} (\text{l}) \] These steps illustrate the detailed progress of the reaction through intermediate states before forming the final products. #### Task: Writing the Rate Law Your task is to write the rate law for this reaction based on the proposed mechanism. To determine the rate law, focus on the slowest step in the mechanism, which is often the rate
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