The reaction 5 Br (aq) + BrO3¯ (aq) + 6H+ (aq) + 3Br2 (1) + 3H20 (I) is expected to obey the mechanism BrO3 (aq) + H* (aq) HBrОз (аq) + Ht (aq) + H2BrO3" (aq) e HBRO3 (aq) - H2BRO3* (aq) (Br-BrO2) (aq) + H20 (1) Fast Fast Slow Br (aq) (Br-BrO2) (aq) + 4H+ (aq) + 4Br (aq) 3B12 (1) + 3H20 (I) Fast Write the rate law.
The reaction 5 Br (aq) + BrO3¯ (aq) + 6H+ (aq) + 3Br2 (1) + 3H20 (I) is expected to obey the mechanism BrO3 (aq) + H* (aq) HBrОз (аq) + Ht (aq) + H2BrO3" (aq) e HBRO3 (aq) - H2BRO3* (aq) (Br-BrO2) (aq) + H20 (1) Fast Fast Slow Br (aq) (Br-BrO2) (aq) + 4H+ (aq) + 4Br (aq) 3B12 (1) + 3H20 (I) Fast Write the rate law.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Chemical Kinetics: Determining the Rate Law for a Reaction
#### The Reaction
The overall reaction being studied is:
\[ 5 \text{Br}^- (\text{aq}) + \text{BrO}_3^- (\text{aq}) + 6\text{H}^+ (\text{aq}) \rightleftharpoons 3 \text{Br}_2 (\text{l}) + 3 \text{H}_2\text{O} (\text{l}) \]
This reaction is expected to follow a specific mechanism to reach its final products.
#### Proposed Reaction Mechanism
The mechanism consists of multiple steps:
1. **First Step (Fast Equilibrium)**
\[ \text{BrO}_3^- (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{HBrO}_3 (\text{aq}) \]
2. **Second Step (Fast Equilibrium)**
\[ \text{HBrO}_3 (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{H}_2\text{BrO}_3^+ (\text{aq}) \]
3. **Third Step (Slow)**
\[ \text{Br}^- (\text{aq}) + \text{H}_2\text{BrO}_3^+ (\text{aq}) \rightarrow (\text{Br-BrO}_2) (\text{aq}) + \text{H}_2\text{O} (\text{l}) \]
4. **Fourth Step (Fast)**
\[ (\text{Br-BrO}_2) (\text{aq}) + 4\text{H}^+ (\text{aq}) + 4\text{Br}^- (\text{aq}) \rightarrow 3\text{Br}_2 (\text{l}) + 3\text{H}_2\text{O} (\text{l}) \]
These steps illustrate the detailed progress of the reaction through intermediate states before forming the final products.
#### Task: Writing the Rate Law
Your task is to write the rate law for this reaction based on the proposed mechanism. To determine the rate law, focus on the slowest step in the mechanism, which is often the rate](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96b52401-77ae-42e3-bef0-cdd66c230602%2F0db51dc9-8c5c-4386-99b0-90537f5e2b1b%2F2onk14o_processed.png&w=3840&q=75)
Transcribed Image Text:### Chemical Kinetics: Determining the Rate Law for a Reaction
#### The Reaction
The overall reaction being studied is:
\[ 5 \text{Br}^- (\text{aq}) + \text{BrO}_3^- (\text{aq}) + 6\text{H}^+ (\text{aq}) \rightleftharpoons 3 \text{Br}_2 (\text{l}) + 3 \text{H}_2\text{O} (\text{l}) \]
This reaction is expected to follow a specific mechanism to reach its final products.
#### Proposed Reaction Mechanism
The mechanism consists of multiple steps:
1. **First Step (Fast Equilibrium)**
\[ \text{BrO}_3^- (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{HBrO}_3 (\text{aq}) \]
2. **Second Step (Fast Equilibrium)**
\[ \text{HBrO}_3 (\text{aq}) + \text{H}^+ (\text{aq}) \rightleftharpoons \text{H}_2\text{BrO}_3^+ (\text{aq}) \]
3. **Third Step (Slow)**
\[ \text{Br}^- (\text{aq}) + \text{H}_2\text{BrO}_3^+ (\text{aq}) \rightarrow (\text{Br-BrO}_2) (\text{aq}) + \text{H}_2\text{O} (\text{l}) \]
4. **Fourth Step (Fast)**
\[ (\text{Br-BrO}_2) (\text{aq}) + 4\text{H}^+ (\text{aq}) + 4\text{Br}^- (\text{aq}) \rightarrow 3\text{Br}_2 (\text{l}) + 3\text{H}_2\text{O} (\text{l}) \]
These steps illustrate the detailed progress of the reaction through intermediate states before forming the final products.
#### Task: Writing the Rate Law
Your task is to write the rate law for this reaction based on the proposed mechanism. To determine the rate law, focus on the slowest step in the mechanism, which is often the rate
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