The reaction: 2P+Q→ R has the following proposed mechanism: Step 1: P+Q=S (fast equilibrium) Step 2: S+Q→T Step 3: T+ P→R+Q If step 2 is the rate-determining step, then the rate of formation of R should equal: O a. K[P]²[Q] Ob. K[P]²[Q]² Oc. K[P][Q]² C. O d. K[P][Q] O e. K[P]
The reaction: 2P+Q→ R has the following proposed mechanism: Step 1: P+Q=S (fast equilibrium) Step 2: S+Q→T Step 3: T+ P→R+Q If step 2 is the rate-determining step, then the rate of formation of R should equal: O a. K[P]²[Q] Ob. K[P]²[Q]² Oc. K[P][Q]² C. O d. K[P][Q] O e. K[P]
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Question 37
The reaction:
2P+Q→ R
has the following proposed mechanism:
Step 1: P+Q=S (fast equilibrium)
Step 2: S+Q→T
Step 3: T+ P→R+Q
If step 2 is the rate-determining step, then the rate of formation of R should equal:
Oa. K[P]²[Q]
Ob. K[P]²[Q]²
Oc. K[P][Q]²
C.
d. K[P][Q]
Oe. K[P]
KAERANGA](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe49ecbb2-f25c-46ea-84a1-b0b9efe71122%2F6c206598-03ed-4364-a090-536126b34069%2F15lf326_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 37
The reaction:
2P+Q→ R
has the following proposed mechanism:
Step 1: P+Q=S (fast equilibrium)
Step 2: S+Q→T
Step 3: T+ P→R+Q
If step 2 is the rate-determining step, then the rate of formation of R should equal:
Oa. K[P]²[Q]
Ob. K[P]²[Q]²
Oc. K[P][Q]²
C.
d. K[P][Q]
Oe. K[P]
KAERANGA
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