The reactance data for the power system shown in below figure in per unit on a common base is as the following: ਮਾ X-X² j0.1 G₁ to j0.25 Select one: O a.-j 1.660 pu O b.-j 5.369 pu O c.-j 4.669 pu O d. No right answer Ti A+ j0.05 Assume that the pre fault voltage at bus 2 = 1.15 pu. For a bolted single line to ground fault (bus 2), the fault current in pu = 2 j0.3 + j0.25 j0.5 3 j0.25 T₂ 38 A j0.25 j0.1 G₂ 1 j0.05

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter9: Unsymmetrical Faults
Section: Chapter Questions
Problem 9.13P: Consider the oneline diagram of a simple power system shown in Figure 9.20. System data in per-unit...
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The reactance data for the power system shown in below figure in per unit on a common base is as the following:
xx 10.1
G₁
j0.25
Ti
Select one:
0 à. - j 1,660 pu
O b. - j 5,369 pu
0 c j 4,669 pu
O d. No right answer
2 j0.3
#
A
1 °
j0.05
j0.25
| Assume that the pre fault voltage at bus 2 = 1.15 pu.
For a bolted single line to ground fault (bus 2), the fault current in pu =
j0.5
3
j0.25
T,
34
A
j0.25
j0.1
G
j0.05
Transcribed Image Text:The reactance data for the power system shown in below figure in per unit on a common base is as the following: xx 10.1 G₁ j0.25 Ti Select one: 0 à. - j 1,660 pu O b. - j 5,369 pu 0 c j 4,669 pu O d. No right answer 2 j0.3 # A 1 ° j0.05 j0.25 | Assume that the pre fault voltage at bus 2 = 1.15 pu. For a bolted single line to ground fault (bus 2), the fault current in pu = j0.5 3 j0.25 T, 34 A j0.25 j0.1 G j0.05
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