The rate of a certain reaction is given by the following rate law: rate wk[N.J[0,] Use this information to answer the questions below. What is the reaction order in N2? What is the reaction order in 03? What is overall reaction order? At a certain concentration of N2 and 03, the initial rate of reaction is 0.970M/ s. What would the initial rate of the reaction be if the concentration of N2 were halved? Round your answer to 3 significant digits. The rate of the reaction is measured to be 3.0 x 103 M / s when [N2] = 1.7 M and [03] = 1.0 M. Calculate the value of the rate constant. Round your answer to 2 significant digits.

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### Reaction Rate Law and Orders

The rate of a certain reaction is given by the following rate law:

\[ \text{rate} = k \left[ \text{N}_2 \right]^3 \left[ \text{O}_3 \right] \]

Use this information to answer the questions below:


| **Question**                                                                                                                                                     | **Answer**         |
|------------------------------------------------------------------------------------------------------------------------------------------------------------------|--------------------|
| What is the reaction order in \( \text{N}_2 \)?                                                                                                                   | \(\boxed{3}\)      |
| What is the reaction order in \( \text{O}_3 \)?                                                                                                                   | \(\boxed{1}\)      |
| What is overall reaction order?                                                                                                                                  | \(\boxed{4}\)      |
| At a certain concentration of \( \text{N}_2 \) and \( \text{O}_3 \), the initial rate of reaction is \( 0.970 \, \text{M/s} \). What would the initial rate of the reaction be if the concentration of \( \text{N}_2 \) were halved? Round your answer to 3 significant digits. | \(\boxed{0.121} \, \text{M/s} \) |
| The rate of the reaction is measured to be \( 3.0 \times 10^3 \, \text{M/s} \) when \([ \text{N}_2 ] = 1.7 \, \text{M} \) and \([ \text{O}_3 ] = 1.0 \, \text{M} \). Calculate the value of the rate constant. Round your answer to 2 significant digits. | \(\boxed{6.1} \, \text{M}^{-3} \cdot \text{s}^{-1} \)    |

### Explanation of Diagrams (If Any)
There are no graphs or diagrams in the image.

### Detailed Explanation:

1. **Reaction Order in \( \text{N}_2 \)**:
   The exponent of \( [ \text{N}_2 ] \) in the rate law equation is 3.
   Therefore, the reaction order with respect to \( \text{N}_2 \) is 3.

2. **Reaction Order in \( \text{O}_3 \)**:
   The exponent of \( [ \text{
Transcribed Image Text:### Reaction Rate Law and Orders The rate of a certain reaction is given by the following rate law: \[ \text{rate} = k \left[ \text{N}_2 \right]^3 \left[ \text{O}_3 \right] \] Use this information to answer the questions below: | **Question** | **Answer** | |------------------------------------------------------------------------------------------------------------------------------------------------------------------|--------------------| | What is the reaction order in \( \text{N}_2 \)? | \(\boxed{3}\) | | What is the reaction order in \( \text{O}_3 \)? | \(\boxed{1}\) | | What is overall reaction order? | \(\boxed{4}\) | | At a certain concentration of \( \text{N}_2 \) and \( \text{O}_3 \), the initial rate of reaction is \( 0.970 \, \text{M/s} \). What would the initial rate of the reaction be if the concentration of \( \text{N}_2 \) were halved? Round your answer to 3 significant digits. | \(\boxed{0.121} \, \text{M/s} \) | | The rate of the reaction is measured to be \( 3.0 \times 10^3 \, \text{M/s} \) when \([ \text{N}_2 ] = 1.7 \, \text{M} \) and \([ \text{O}_3 ] = 1.0 \, \text{M} \). Calculate the value of the rate constant. Round your answer to 2 significant digits. | \(\boxed{6.1} \, \text{M}^{-3} \cdot \text{s}^{-1} \) | ### Explanation of Diagrams (If Any) There are no graphs or diagrams in the image. ### Detailed Explanation: 1. **Reaction Order in \( \text{N}_2 \)**: The exponent of \( [ \text{N}_2 ] \) in the rate law equation is 3. Therefore, the reaction order with respect to \( \text{N}_2 \) is 3. 2. **Reaction Order in \( \text{O}_3 \)**: The exponent of \( [ \text{
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