The rate constant of the elementary reaction HCOOH(g)CO2(g) +H2(g) is k- 1.65×10, at 471°C, and the reaction has an activation energy of 203 kJ mol". (a) Compute the rate constant of the reaction at a temperature of 779°c. (b) At a temperature of 471°C, 4.20x10" s is required for half of the HCOOH originally present to be consumed. How long will it take to consume half of the reactant if an identical experiment is performed at 779°C?

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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The rate constant of the elementary reaction
HCOOH(g) CO2(g) +H2(g)
is k-1.65x101 at 471°C, and the reaction has an activation energy of 203 kJ mol".
(a) Compute the rate constant of the reaction at a temperature of 779°c.
(b) At a temperature of 471°C, 4.20x10* s is required for half of the HCOOH originally present to be consumed. How long will it take to
consume half of the reactant if an identical experiment is performed at 779°C?
Transcribed Image Text:The rate constant of the elementary reaction HCOOH(g) CO2(g) +H2(g) is k-1.65x101 at 471°C, and the reaction has an activation energy of 203 kJ mol". (a) Compute the rate constant of the reaction at a temperature of 779°c. (b) At a temperature of 471°C, 4.20x10* s is required for half of the HCOOH originally present to be consumed. How long will it take to consume half of the reactant if an identical experiment is performed at 779°C?
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